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Vesna [10]
3 years ago
7

Independent Practice

Mathematics
1 answer:
kykrilka [37]3 years ago
4 0

Answer:

C.

0.5; 13.5; 1093.5

Step-by-step explanation:

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Need help ASAP Geometry
nadya68 [22]

Answer:

Step-by-step explanation:

5x-1 is twice the bisector angle 4x-17 so

5x-1=2(4x-17)

5x-1=8x-34

-3x=-33

x=11, abc=5x-1

5(11)-1=54

8 0
3 years ago
Two cars, one going due east at 25 m / sec and the second going due south at 50/3 m / sec are traveling toward the intersection
valkas [14]

Answer:

30 m/s

Step-by-step explanation:

Let's say the distance from the first car to the intersection is x, and the distance from the second car to the intersection is y.

The distance between the cars can be found with Pythagorean theorem:

d² = x² + y²

Taking derivative with respect to time:

2d dd/dt = 2x dx/dt + 2y dy/dt

d dd/dt = x dx/dt + y dy/dt

We know that x = 200, dx/dt = -25, y = 150, and dy/dt = -50/3.

To find dd/dt, we still need to find d.

d² = x² + y²

d² = (200)² + (150)²

d = 250

Plugging everything in:

250 dd/dt = (200) (-25) + (150) (-50/3)

dd/dt = -30

The cars are approaching each other at a rate of 30 m/s at that instant.

4 0
3 years ago
Please answer correct with an explanation thanks!
Strike441 [17]

Answer:

17/50

Step-by-step explanation:

P(red or purple) = number of red or purple / total

There are 7 red rings and 10 purple rings

                          = (7+10) / 50

                          = 17/50

3 0
3 years ago
Read 2 more answers
Cashews cost $6.45 a
almond37 [142]

Answer:

$20.96

Step-by-step explanation: 6.45 times three equals 19.35 plus a quarter of 6.45 equals 1.6125 which you round to 1.61. So 19.35+1.61= 20.96

8 0
3 years ago
(y+6)^2-(y-2)^2 <br><br> I got 16y+26 but it is wrong?
Gemiola [76]

Answer:

16y + 32

Step-by-step explanation:

Expand each term.

(y+6)² - (y-2)²

= (y+6)(y+6) - (y-2)(y-2)

= y² + 12y + 36 - (y² - 4y + 4)

Subtract the second group by changing each term's signs

= y² + 12y + 36 - y² + 4y - 4

Collect like terms

= 16y + 32

5 0
3 years ago
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