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miv72 [106K]
4 years ago
13

Factor the expression completely.

Mathematics
1 answer:
densk [106]4 years ago
3 0

Answer:

\fbox{\begin{minipage}{13em}Option D: 2(3x + 4)(3x - 4)\end{minipage}}

Step-by-step explanation:

      A = 18x^{2}  - 32\\

Find the sharing components:

<=> A=2*9*x^{2} - 2*16

Apply the inverse of associative property:

<=> A = 2(9x^{2} - 16)

Identify two square components inside the parenthesis:

<=> A = 2((3x)^{2} - 4^{2} )

Factorize:

<=> A = 2(3x + 4)(3x - 4)

=> Option D is correct

Hope this helps!

:)

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The dimensions of a triangular prism are given in the diagram find the volume of the prism in cubic feet .
nata0808 [166]

Answer:

B. 192.5 ft³

To find the volume of a triangle prism, multiply the base, height, and length together, and then divide it by 2 (or multiply that by 0.5).

(5 * 7 * 11)/2

Multiply 5 by 7 to get 35.

(35 * 11)/2

Multiply 35 by 11 to get 385.

385/2

192.5 ft³ is the volume of this triangluar prism.

4 0
3 years ago
Read 2 more answers
Convert
Rzqust [24]
The answer is A. 0.12 using the long division method.
See attachment below.
Hope it helped!

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4 years ago
In the library on a university campus, there is a sign in the elevator that indicates a limit of 16 persons. Furthermore, there
yan [13]

Answer:

Explained below.

Step-by-step explanation:

According to the Central Limit Theorem if an unknown population is selected with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from this population with replacement, then the distribution of the sample means will be approximately normally.  

Then, the mean of the sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

a

The expected value of the sample mean of their weights is same as the population mean, <em>μ</em> = 1515 lbs.

b

The standard deviation of the sampling distribution of the sample mean weight is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{25}{\sqrt{16}}=6.25

c.

The average weights for a sample of 16 people will result in the total weight exceeding the weight limit of 2500 lbs. is:

\text{Average Weight}=\frac{2500}{16}=156.25

d

Compute the probability that a random sample of 16 persons on the elevator will exceed the weight limit as follows:

P(\bar X > 156.25)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{156.25-151}{6.25})\\\\=P(Z>0.84)\\\\=1-P(Z

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I'm pretttty sure it's 216
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