Question

Identify the equation of the circle that has its center at (9, 12) and passes through the origin.

Answer 1

Answer:

(x-9)^2 +(y-12)^2 = 225

Step-by-step explanation:

First find the length of the radius

If is the distance from the center to the point

d = sqrt( (x2-x1)^2 + (y2-y1)^2 )

   = sqrt( (0-9)^2 + (0-12)^2)

   = sqrt ( 81+144)

  = sqrt(225)

  = 15

The equation for a circle is

( x-h) ^2+ (y-k)^2 = r^2

(x-9)^2 +(y-12)^2 = 15^2

(x-9)^2 +(y-12)^2 = 225