The sum of two numbers is 14. The first number 2/5<br> of the second number. What are the numbers?

Use the picture to figure out the 4 digit number combination.

professor190 [17]

3574 it’s the number of books each kids has

7 0

3 years ago

Read 2 more answers

Fernando factored 45y^6 as (9y^3)(5y^3).

marishachu [46]

Answer:

They both factored it correctly

Step-by-step explanation:

To find the one that was factored correctly, we expand the two of them and compare with $45y^6$ .

Fernando

$(9y^3)(5y^3)$

= $9 * 5 * y^3 * y^3$

= $45y^6$

Salma

$(3y)(15y^5)$

= $3 * 15 * y * y^5$

= $45y^6$

As we can see, they both factored it correctly.

4 0

3 years ago

What is 900cm/h = cm/min? ( with an explanation not just the answer)

vladimir2022 [97]

I hope that helped :)

6 0

4 years ago

PLEASE HELP! WILL GIVE 70 POINTS!!

Tresset [83]

Answer:

$A=189\ mm^2$

Step-by-step explanation:

<u>Surface Areas </u>

Is the sum of all the lateral areas of a given solid. We need to compute the total surface area of the given prism. It has 5 sides, two of them are equal (top and bottom areas) and the rest are rectangles.

Computing the top and bottom areas. They form a right triangle whose legs are 4.5 mm and 6 mm. The area of both triangles is

$\displaystyle A_t=2*\frac{b.h}{2}=b.h=(4.5)(6)=27 mm^2$

The front area is a rectangle of dimensions 7.7 mm and 9 mm, thus

$A_f=b.h=(7.5)(9)=67.5 \ mm^2$

The back left area is another rectangle of 4.5 mm by 9 mm

$A_l=b.h=(4.5)(9)=40.5 \ mm^2$

Finally, the back right area is a rectangle of 6 mm by 9 mm

$A_r=b.h=(6)(9)=54 \ mm^2$

Thus, the total surface area of the prism is

$A=A_t+A_f+A_l+A_r=27+67.5+40.5+54=189\ mm^2$

$\boxed{A=189\ mm^2}$

4 0

3 years ago

Suppose 60% of American adults believe Martha Stewart is guilty of obstruction of justice and fraud related to insider trading.

Ierofanga [76]

Answer:

Since the sample size is large enough (n>30) and the probability of success is near to 0.5, and we have that $n\hat p = 60>10$ and $n(1-\hat p) = 40>10$ we can assume that the distribution for $\hat p$ is normal

The population proportion have the following distribution

$\hat p \sim N(\hat p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The mean is given by:

$\mu_p = 0.6$

$\sigma_p = \sqrt{\frac{0.6*(1-0.6)}{100}}=0.04899$

So then we can conclude that the best answer would be:

c. approximately Normal, with mean 0.6 and standard error 0.04899

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p$ represent the real population proportion of interest

$\hat p$ represent the estimated proportion for the sample

n is the sample size required (variable of interest)

Solution to the problem

Since the sample size is large enough (n>30) and the probability of success is near to 0.5, and we have that $n\hat p = 60>10$ and $n(1-\hat p) = 40>10$ we can assume that the distribution for $\hat p$ is normal

The population proportion have the following distribution

$\hat p \sim N(\hat p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The mean is given by:

$\mu_p = 0.6$

$\sigma_p = \sqrt{\frac{0.6*(1-0.6)}{100}}=0.04899$

So then we can conclude that the best answer would be:

c. approximately Normal, with mean 0.6 and standard error 0.04899

8 0

3 years ago

The sum of two numbers is 14. The first number 2/5 of the second number. What are the numbers?