Which is the formula infinding the volume of a rectangular prism?

Mathematics

2 answers:

Brrunno [24]2 years ago

8 0

<h3>Volume of a rrectangular prism= width×length×height</h3>

andrew11 [14]2 years ago

6 0

Answer:

Pretty sure the formula is l × w × h = V

length × width × height = Volume

You might be interested in

The ratio of SAMs age to hank is 5 to 3. If the sum of their age is 24. How old is is hank?

Serggg [28]

Lets consider SAM's age is 'x' and Hank's age is 'y'
So as per given data Sam's age is 5/3 times of Hank's age
so x = 5/3 * y
3x = 5y --> equation 1
and also sum of their ages is 24
so, x + y = 24
we need to find Hank's age (y)
so x = 24 - y
Now replace x value in equation 1
3(24-y) = 5y
72-3y = 5y
72 = 3y+5y
8y= 72
y= 72/8
y = 9 years.

So the Hank's age is 9 years

.

3 0

2 years ago

I don’t know how to do this

stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as $x$ approaches the edges. For example,

$g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}$

has two pieces, $2x+5$ and $x^2-10$ , both of which are continuous by themselves on the provided intervals. In order for $g$ to be continuous everywhere, we need to have

$\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)$

By definition of $g$ , we have $g(-3)=2(-3)+5=-1$ , and the limits are

$\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1$

$\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1$

The limits match, so $g$ is continuous.

For the others: Each of the individual pieces of $f,h$ are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.