Answer:
x=6
Step-by-step explanation:
5x^2-136=44
add 136 to both sides
5x^2=180
divide both sides by 5
x^2= 36
take square root of both sides
x=6
Answer:
y =
- 8
Step-by-step explanation:
given slope m = 
point (5, -2) for (x1, y1)
equation for point slope form
y - y1 = m(x- x1)
y - (-2) =
(x -5)
y + 2 =
x - 6, simplify
y =
- 8,
further you can multiply by 5 to get rid of fraction
5y = 6x - 40
Answer:








Step-by-step explanation:
Given



Solving (a): NK
MK is a diagonal and NK is half of the diagonal. So:



Solving (b): JL
JL is a diagonal, and it is twice of NL.



Solving (c): KL
To solve for KL, we consider triangle KNL where:

and





Solving (d - h):
To do this, we consider triangle JKN
-- diagonals bisect one another at right angle
Alternate interior angles are equal. So:

Similarly:


So:







Step-by-step explanation:
one second 12345678910
C.4/11 is the answer to your question