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klemol [59]
3 years ago
5

Brenda and Lynne cut shapes from

Mathematics
1 answer:
Fed [463]3 years ago
8 0

Answer:

8

Step-by-step explanation:

32/4

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True or False, 15%-54% of errors reported from primary care practices are related to the testing process.
vovikov84 [41]

Answer:

i would say true

Step-by-step explanation:

5 0
3 years ago
When The sum of 1. 3240 and 1. 4872 is subtracted from 4. 0121 it will give you the difference of
Paladinen [302]

Answer:

C. 1.2009

Step-by-step explanation:

1.3240 + 1.4872 = 2.8112

4.0121 - 2.8112 = 1.2009 - C

8 0
3 years ago
Use the x-intercept method to find all real solutions of the equation.x3-10x2=27x-18=0
g100num [7]

x^3-10x^2=27x-18=0 has no solutions

x^3-10x^2-27x-18=0 has 3 solutions

x^3-10x^2-27x-18=0 also has three solutions


3 0
3 years ago
a trapezoide has an area of 150 square meters. If the bases are 14 meters and 16 meters, what is the height of the trapezoid​
SIZIF [17.4K]

Answer:

h = 10 m

Step-by-step explanation:

The formula for area of a trapezoid is  

A = (1/2)(B + b)h   where B is the bottom base, b is the top base, and h is the height.  

We are given B = 16, b = 14, and A = 15, plug those values in and simplify

150 = (1/2)(16 + 14)(h)

      150 = (1/2)(30)(h)

          150 = (15)h             (half of 30 is 15)

                10 m =  h       (divide both sides by 15 to isolate h)

6 0
3 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
RoseWind [281]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
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