Question

The function below is written in vertex form or intercept form. Rewrite them in standard form and show your work.

Answer 1

Answer:

The standard form as $y =-3x^2+18x-24$

Step-by-step explanation:

Given: A function which is written in vertex form or intercept form.

We have to re-write it  in standard form that in terms of $y=ax^2+bx+c$

Given $y =-3 (x-2)(x-4)$

Multiply each term on the right side, we get,

$y =-3[x(x-4)-2(x-4)]$

$y =-3[x^2-4x-2x+8]$

$y =-3[x^2-6x+8]$

Multiply constant term , we get,

$y =-3x^2+18x-24$

Thus , we have obtained the standard form as $y =-3x^2+18x-24$

Answer 2

Answer:

The standard form is: y = -3x² +18x -24.

Step-by-step explanation:

Given is y = -3(x-2)(x-4)

Using FOIL method to expand the parentheses:-

y = -3(x-2)(x-4)

y = -3(x² -2x -4x +8)

Combining like terms:-

y = -3(x² -6x +8)

Distributing -3 to the terms inside parentheses:-

y = -3x² +18x -24.

Hence, standard form is: y = -3x² +18x -24.