Answer:
On the left the one down below
Step-by-step explanation: I check it to make sure it was right
Remark
That was well worth doing. Desmos gave you the answer to the graph. Unfortunately I can only give you the correct graph. You will have to figure out from the choices which one is the correct answer -- or edit it so I can see what the rest of the question is.
Graph
The red one is f(x) is x + 3 {x <= -2}
The blue one is f(x) is x^2 - 1 {-2 <x <1} Notice the gap at 2. It is not continuous
The green one is f(x) is log_2(-x + 3) {1 <=x < 3} and there is a gap between the blue and green one.
-- The filler pipe can fill 1/6 of the pool every hour.
-- The drainer pipe can drain 1/10 of the pool every hour.
-- When they're filling and draining at the same time, the filler pipe
will win eventually, because it finishes more of the pool in an hour
than what the drain pipe can finish in an hour.
-- When they're filling and draining at the same time, then every hour,
1/6 of the pool fills and 1/10 of it empties. The difference is (1/6) - (1/10).
To do that subtraction, we need a common denominator.
The smallest denominator that works is 30.
1/6 = 5/30
1/10 = 3/30 .
So in every hour, 5/30 of the pool fills, and 3/30 of the pool empties.
The result of both at the same time is that 2/30 = 1/15 fills each hour.
If nobody notices what's going on and closes the drain pipe, it will take
<em><u>15 hours</u></em> to fill the pool.
If the drain pipe had <em><u>not</u></em> been open, the filler pipe alone could have filled
the pool <em><u>2-1/2 times</u></em> in that same 15 hours. With both pipes open,
1-1/2 pool's worth of water went straight down the drain during that time,
and it was wasted.
I would say that the school should take the cost of 1-1/2 poolsworth out
of Ms. Charles' pay at the rate of $5 a week. I would, but that would
guarantee her more job security than she deserves after pulling a stunt
like that.
I hope this did not take place in California.
I can’t read the question, what is the question?
