Jenny is comparing the cost of two packages of socks.One package has 8 pairs of socks for $12.Another package has 3 pairs of soc
1 answer:
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Answer:
1521.16402
Step-by-step explanation:
use fraction- division format
Multiply the numerator and denominator by 100
Reduce by 2
Now do long division
1521. 164022
189|287500
- 189
985
- 945
400
- 378
220
- 189
310
- 189
1210
- 1134
760
- 756
40
- 0
400
- 378
22
Answer:
x = 12
Step-by-step explanation:
To solve this and show your work, you have to start of with the equation (3x - 6) = 30.
You then have to add 6 to both sides like this:
So then the 6 is cancelled out, and you are left with
3x = 36.
Now you just have to divide both sides by 3 like this:
Which cancels 3 out, and you are left with
x = 12.
Answer:
The first step is calculate the degrees of freedom, on this case:
Since is a one side right tailed test the p value would be:
And for this case we can conclude that:
And we will reject the null hypothesis at since
Step-by-step explanation:
Data given and notation
represent the mean height for the sample
represent the sample standard deviation
sample size
represent the value that we want to test
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the mean is higher than 15, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
For this case the statistic is given:
P-value
The first step is calculate the degrees of freedom, on this case:
Since is a one side right tailed test the p value would be:
And for this case we can conclude that:
And we will reject the null hypothesis at since