Two binders costs$4.36. how many bindees can buy with $55?

Mathematics

2 answers:

Reil [10]2 years ago

6 0

Answer:

Step-by-step explanation:

First you need to find the price for one binder. If 2 binders cost 4.36 you have to divide by 2 to find the price for 1. You should get 2.18. Then you have to see how many times you can multiply 2.18 without having the product go over 2.18. 2.18 • 22 = 47.96, the number closest to 50 without going over. Therefore, she can buy 22 binders.

cupoosta [38]2 years ago

6 0

Answer:

We can by 25 binders for $55.

Step-by-step explanation:

You could either find the unit cost per binder or write and solve an equation of ratios.

If we use an equation of ratios:

$4.36 2

------------ = ------

$55 x

Cross-multiplying, we get 4.36x = 110. Performing this division, we end up with x = 25.30, which must be rounded down to x = 25 (binders).

We can by 25 binders for $55.

You might be interested in

There are 25 students in Mr.Ash's class touring three levels of a museum. Find the total number of steps the students climbed by

nalin [4]

Answer: 106 total steps

Step-by-step explanation: add all of the total steps to get your answer

8 0

2 years ago

Help!!! I need the answer ASAP!!!

SIZIF [17.4K]

Answer: by combining 1/4 and 1/3 and then you find the amount of left over dog food. Multiply the fractions so they have common denominators, then add. You will get 3/12 + 4/12 = 7/12. 12 - 7 = 5, so there is 5/12 of the bag left.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find f if f′(x)=2x−3/x^4, x>0 and f(1)=2.

slavikrds [6]

$f'(x)=2x-\dfrac3{x^4}$
$\displaystyle\int f'(x)\,\mathrm dx=\int\left(2x-\frac3{x^4}\right)\,\mathrm dx$
$f(x)=x^2+\dfrac1{x^3}+C$

Given that $f(1)=2$ , we get

$2=1^2+\dfrac1{1^3}+C$
$2=2+C$
$\implies C=2$

so that

$f(x)=x^2+\dfrac1{x^3}$