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saul85 [17]
3 years ago
15

Instructions: Find the missing side lengths. Leave your answers as radicals in simplest form.

Mathematics
1 answer:
KengaRu [80]3 years ago
7 0

Answer:

X=6 and Y=3

Step-by-step explanation:

Use SOHCAHTOA, SOH, Sin=Opposite/Hypotenuse, Therefore Sin60°=(3√3)/x ; Xsin60°=3√3 and Sin60° without using 4figuretable or calculator is √3/2, Now x=3√3 ÷√3/2 ;. therefore X=3√3×2/√3= 6. X=6 . Using Pythagoras theorem, 6²={(3√3)² +y²}. Y²= 36-27=9. Y=√9, Y=3. Therefore X=6 and Y=3.

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4x^5 is a term of degree 5, and its coefficient is 4
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4 years ago
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Two mechanics worked on a car. The first mechanic worked for 15
4vir4ik [10]

Answer:

First: $65

Second: $115

Step-by-step explanation:

We write equations for each part of this situation.

<u>The Total Charge</u>

Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.

<u>The Sum of the Rates</u>

Since the first's rate is a and the second is b, we can write a+b=180 since their sum is 180.

We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.

For a+b=180, rearrange to b=180-a and substitute into 15a+5b=1550.

15a + 5 (180-a)=1550

15a+900-5a=1550

10a+900-900=1550-900

10a=650

a=$65 was charged by the first mechanic.

We substitute to find the second mechanic's rate.

65+b=180

65-65+b=180-65

b= $115 was charged by the second mechanic

4 0
3 years ago
What is the quotient of 2 ÷ 2/3?​
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Answer:

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Step-by-step explanation:

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Jobisdone [24]
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7 0
4 years ago
The areas of the squares adjacent to two sides of a right triangle are shown below
Dahasolnce [82]

Answer:

The area of the square is 85 units^2

Step-by-step explanation:

Okay, here in this question, we are interested in calculating the area of the unknown square.

Kindly note that, since each of the other shapes are squares too, it means that the length of their sides is simply the square root of their areas.

Thus, the length of the squares are ;

√35 units and √50 units respectively

Now to find the area of the larger square, we employ the use of Pythagoras’ theorem which states that the square of the hypotenuse is equal to the sum of the squares of the two other sides

Let’s call the unknown length X

x^2 = (√35)^2 + (√50)^2

x^2 = 35 + 50

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x = √85 units

Now as we know that the area of a square is simply the length of the side squared,

The area of the biggest square is simply (√85)^2 = 85 units^2

8 0
4 years ago
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