Notice the x^-2, this is equal to 1/x^2. Then notice the y^0, any value raised to the zero power is equal to 1, ie n^0=1. So your expression is actually just:
8/x^2, the y value has no effect upon the output. They want you to evaluate, which must means calculate, the value when x=2 so:
8/(2^2)
8/4
2
Answer:
D. v=<20, 52>
Step-by-step explanation:
Vector u can be written in component form by subtracting its initial point from its terminal point:
u = (5, -4) -(15, 22) = <-10, -26>
We are told that v = -2u, so ...
v = -2<-10, -26> = <20, 52>
_____
Multiplying a vector by -1 reverses its direction; multiplying it by some factor k changes its magnitude by a factor of k. To reverse the direction and double the magnitude, we can multiply u by -2.
If the equation is in the form of y = mx + C, where m and C are real numbers, the slope (which means gradient) of the line is the coefficient of x (I.e. the number to the left of x in simple language), which is m.
In this case, m = 54 and C = -13pie. Both are real numbers, which means that this equation satisfies the form of y = mx + C
m is the coefficient of x, which is 54. 54 is the gradient of this line, which means that for every 54 y-axis units the line increases, the line increases 1 x-axis unit.
Hope this helps! :)
-5a^2 - 7a = -a x (5a + 7)
let me know if you have any other questions
:)
