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dem82 [27]
3 years ago
11

Help please i’m desperate

Mathematics
2 answers:
Alexxx [7]3 years ago
5 0
The answer is a im pretty sure
Licemer1 [7]3 years ago
5 0
Yes I can confirm "a" is the right answer. Y is represented by the perpendicular line and X by the horizontal line.

The intersection on both coordinates is O (zero).

On the X coordinate all the square on the right of zero are poziti (ex: 5 or +5). On the left side are the negative or minus numbers.

The same applies to the Y coordinate: above zero is positive , undet zero is negative.

Therefore you just have to count the squared starting from the intersection (zero): hom many on the right(positive), left(negative), up(positive) and down(negative).

So we have:
On X axis
right: +5
Left: -4

On Y axis
Up:+3
Down: -2.

The answer is "a".
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Mark C.

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3 years ago
Determine how many zeros, how many real or complex, and find the roots for f(x) = x3 − 5x2 − 25x + 125.
miskamm [114]
We can write this as:-

P(x) = + x^3 - 5x^2 - 25x + 125
There are 2 changes of real sign so by Descartes Rule of  signs there are either 2  positive real roots or 0 positive roots.

P(-x)  = - x^3 - 5x^2 + 25x + 125 
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125 is a multiple of 5 so By rational root theorem  5 could be  a positive root.

P(5) =  125 - 125 - 125 + 125  = 0   so one zero is  5
if we divide   the polynomial by (x - 5) we get the quadratic
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x = 5,-5

so the roots are 5 (multiplicity 2)  and -5.
2 real positive zeroes  and one real negative zero
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