The solution is -4/9x + 1
Hypotenuse² = perpendicular² + base²
H² = 20²+21²
H²= 400+441 = 841
H = √841
H = 29 cm
Answer:
Mark C.
Step-by-step explanation:
If there are 27 students in both classes, it's logicial to multiply both classes by two to get the total students.
Since the <em>S</em> stands for the students absent, that should come after the brackets.
We can write this as:-
P(x) = + x^3 - 5x^2 - 25x + 125
There are 2 changes of real sign so by Descartes Rule of signs there are either 2 positive real roots or 0 positive roots.
P(-x) = - x^3 - 5x^2 + 25x + 125
There is just one change of sign so there is exactly 1 real negative root.
125 is a multiple of 5 so By rational root theorem 5 could be a positive root.
P(5) = 125 - 125 - 125 + 125 = 0 so one zero is 5
if we divide the polynomial by (x - 5) we get the quadratic
x^2 - 25
(x + 5)(x - 5) = 0
x = 5,-5
so the roots are 5 (multiplicity 2) and -5.
2 real positive zeroes and one real negative zero