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3 years ago

Using a line of best fit, which value would most likely be predicted for an x-value of 16?

Mathematics

1 answer:

jasenka [17]3 years ago

5 0

The answer should be 6

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Show that <img src="https://tex.z-dn.net/?f=%5Csqrt%7B20%7D%20%3D2%5Csqrt%7B5%7D" id="TexFormula1" title="\sqrt{20} =2\sqrt{5}"

Jobisdone [24]

Sqrt(20) = sqrt( 4*5) = 2 root(5)

Mark brainliest please

Hope this helps you

7 0

3 years ago

How do I do it <br> I do not understand I need help

TiliK225 [7]

Which problem do u need help on

4 0

3 years ago

Henry located 2 1/4 and 2.1 on a number line. He wrote the following related story:

Rzqust [24]

Answer:

Jerry ran a farther distance and not Henry.

Step-by-step explanation:

We are given the following information in the question:

Jerry rain $2\frac{1}{2}$ miles and Henry ran 2.1 miles.

Henry claimed that he ran a farther distance.

This is a wrong claim because when we compare:

$2\frac{1}{2}$ and 2.1

$2\displaystyle\frac{1}{2} = \displaystyle\frac{5}{2} = 2 + 0.5 = 2.5\\\\2.5 > 2.1$

Hence, Jerry ran a farther distance and not Henry.

Henry may have made some mistake in plotting $2\frac{1}{2}$ and 2.1 on the number line.

4 0

3 years ago

I forgot how to solve equations such as 3x+5y=-5. Can you give me examples?

maria [59]

Well 3x is 3 times if they are together beside each other that mean they are multiplying so 3 times x plus 5times y = -5

7 0

3 years ago

Read 2 more answers

In the city of Carmen, there is a drawbridge that is opened twice per hour over the summer. The graph below shows the number of

n200080 [17]

Answer:

1) Between 0 and 1 minute the rate of change is 25 ft./min

2) Between 1 and 2 minute the rate of change is 0 ft./min

3) Between 2 and 4 minute the rate of change is -12.5 ft./min

Step-by-step explanation:

1) Between 0, and 1 feet, we have;

The rate of change = (Final height - Initial height)/(Final time - Initial time)

The rate of change = (40 - 15)/(1 - 0) = 25 ft/min

Between 0 and 1 minute the rate of change = 25 ft./min

2) Between 1, and 2 feet, we have;

The rate of change = (40 - 40)/(2 - 1) = 0 ft/min

Between 1 and 2 minute the rate of change = 0 ft./min

3) Between 2, and 4 feet, we have;

The rate of change = (15 - 40)/(4 - 2) = -12.5 ft/min

Between 2 and 4 minute the rate of change = -12.5 ft./min

7 0

3 years ago