First can be a trophy second can be a gold metal and third can be a silver metal.
Answer:
Probability to draw a club and second card is red without replacement will be
or 12.75%
Step-by-step explanation:
A standard deck of cards contains number of cards = 52
And a standard deck contains number of club = 13
Now the probability of first card to be a club will be
![P_{1}=\frac{\text{Number of club in a deck}}{\text{Total number of cards}}](https://tex.z-dn.net/?f=P_%7B1%7D%3D%5Cfrac%7B%5Ctext%7BNumber%20of%20club%20in%20a%20deck%7D%7D%7B%5Ctext%7BTotal%20number%20of%20cards%7D%7D)
= ![\frac{13}{52}=\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B52%7D%3D%5Cfrac%7B1%7D%7B4%7D)
Now this card is separated from the deck.
Therefore, number of remaining cards = 52 - 1 = 51
Second card has been drawn from the deck without replacement.
Since number of red cards in the deck = 13 + 13 = 26
Probability of the second card drawn = ![\frac{\text{Number of red cards}}{\text{Number of remaining cards}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BNumber%20of%20red%20cards%7D%7D%7B%5Ctext%7BNumber%20of%20remaining%20cards%7D%7D)
![P_{2}=\frac{26}{51}](https://tex.z-dn.net/?f=P_%7B2%7D%3D%5Cfrac%7B26%7D%7B51%7D)
Now probability that the first card is a club and the second card is red = ![P_{1}\times P_{2}=\frac{1}{4}\times \frac{26}{51}](https://tex.z-dn.net/?f=P_%7B1%7D%5Ctimes%20P_%7B2%7D%3D%5Cfrac%7B1%7D%7B4%7D%5Ctimes%20%5Cfrac%7B26%7D%7B51%7D)
= ![\frac{13}{102}](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B102%7D)
Or
%
Therefore, probability to draw a club and second card is red without replacement will be
or 12.75%
Answer:C
Step-by-step explanation:
Answer:
(The common base is 2).
Step-by-step explanation:
You have the equation given in the problem:
![2^{(x+3)}-3=5](https://tex.z-dn.net/?f=2%5E%7B%28x%2B3%29%7D-3%3D5)
Then base of
is 2. Therefore, the common base must be 2.
If you add 3 to both sides of the equation, you obtain:
![2^{(x+3)}-3+3=5+3](https://tex.z-dn.net/?f=2%5E%7B%28x%2B3%29%7D-3%2B3%3D5%2B3)
![2^{(x+3)}=8](https://tex.z-dn.net/?f=2%5E%7B%28x%2B3%29%7D%3D8)
If you descompose 8 into its prime factors, you obtain that it can be written as:
8=2*2*2=2³
Therefore, you can you rewrite each side of the equation as following:
![2^{(x+3)}=2^{3}](https://tex.z-dn.net/?f=2%5E%7B%28x%2B3%29%7D%3D2%5E%7B3%7D)
Where the common base is 2.
2 times the amount of cookies Sarah sold is no less than 240, the amount of cookies Kelly sold.