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2 years ago

What is the approximate equation of this line of best fit in slope-intercept form?

Mathematics

2 answers:

podryga [215]2 years ago

8 0

Answer:

Step-by-step explanation:

y = negative 13 over 10x + 13 is the best choice. (0, 13) is the y-intercept. If we begin at (0, 13) and move approximately 10 units to the right, y decreases by 13, so the slope is m = -13/10.

Writing y = negative 13 over 10x + 13 as y = negative 13 over 10 plus 13 would be clearer. We must emphasize that the slope is -13/10 and that this should be enclosed in parentheses: y = (negative 13 over 10)x + 13.

Anni [7]2 years ago

7 0

Answer: y = negative 10 over 13x + 13

Step-by-step explanation: might not be right but im 70% sure it can be but make sure to check

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What is the square root of 312

pishuonlain [190]

Answer:±17.6635217326557

Step-by-step explanation:

5 0

3 years ago

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

8 0

3 years ago

Consider the problem $minimize$ $f(x)=x^4-1$. solve this problem using newton's method. start from $x_0=4$ and perform three ite

stellarik [79]

F(x)=x⁴-1
f'(x)=4x³
Newton’s Method: x[n+1]=x[n]-f(x[n])/f'(x[n]); x[n+1]=x[n]-(x[n]⁴-1)/4x[n]³
x₁=3.00390625
x₂=2.26215...
x₃=1.7182...

X'=X-(X⁴-1)/4X³=X-X/4+1/4X³ is a symbolic way of writing the recursive formula, where X' represents the next iteration.
When X'≈X, -X/4+1/4X³≈0; so X/4≈1/4X³; X≈1/X³, so X⁴≈1 and X⁴-1≈0. But this is f(x)≈0. Hence Newton’s Method converges to a solution.
The rate of change is x[n+1]-x[n]=-(x[n]⁴-1)/4x[n]³=x[n]/4-1/4x[n]³ or symbolically -X/4+1/4X³.
Note that the method converges to one solution. A different x₀ will possibly converge to the solution x=-1.

5 0

3 years ago

Solve this quadratic equation by completing the square.

nadya68 [22]

Answer:

$x=-3+\sqrt{27}\\ x=-3-\sqrt{27}$

Step-by-step explanation:

Let's find our C value for the quadratic equation.

$(\frac{6}{2})^{2} = 9$

That is our C. Since we added 9 to one side, we have to do the same to the other. We get:

$x^{2} +6x + 9 = 18 + 9\\x^{2} +6x + 9 = 27$

Now, lets form the left side as a binomial squared.

$(x+3)^{2} = 27$

Let's square both sides now:

$x+3 = (+/-)\sqrt{27}$

Now, we subtract 3 from both sides to isolate the variable, X:

$x= -3(+/-)\sqrt{27}$

This means that the answers are:

$x=-3+\sqrt{27}\\ x=-3-\sqrt{27}$

I do not understand your answers though. Answer A makes no sense, answer B is 221, answer C is 115, and answer D also does not make sense. If you could clarify this portion, maybe I can help you find your alphabetic answer

3 0

3 years ago

What is the value of x in the model below?

Arturiano [62]

i think its -3

hope its right and helpful

if it is then mark brainlyist

6 0

3 years ago

Read 2 more answers