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Minchanka [31]
3 years ago
8

4.89 gallons of milk is sold for $12.79. If you have $21.44 in your wallet. How many

Mathematics
1 answer:
Mariulka [41]3 years ago
5 0

Answer:

You can buy 8.18 gallons of milk.

Step-by-step explanation:

12.79/4.89 = 2.62

21.44/2.62 = 8.18

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Solve for x: 3(x-5)+4x-2=4​
zysi [14]

Answer:

x = 3

Step-by-step explanation:

3(x−5)+4x−2=4

Step 1: Simplify both sides of the equation.

3(x−5)+4x−2=4

(3)(x)+(3)(−5)+4x+−2=4(Distribute)

3x+−15+4x+−2=4

(3x+4x)+(−15+−2)=4(Combine Like Terms)

7x+−17=4

7x−17=4

Step 2: Add 17 to both sides.

7x−17+17=4+17

7x=21

Step 3: Divide both sides by 7.

7x

7

=

21

7

x=3

3 0
3 years ago
Read 2 more answers
Rani takes a 40-question test. She answers 5% of the questions incorrectly
Feliz [49]

Answer:

2 Questions.

Step-by-step explanation:

To calculate a how much a percentage is of a number, you multiply the number by the percent.

So, we have the equation:

40 x 0.05 = 2

So, Rani got 2 questions incorrect.

Hope this helps!

5 0
3 years ago
Cameron 's book log shows he read a total of 1 1/2 hours each week for 4 weeks. How many total minutes did he read?
Nataly [62]

Answer:

  360 minutes

Step-by-step explanation:

(1.5 h/wk)·(4 wk)·(60 min/h) = 1.5·4·60 min = 360 min

Multiply reading time per week by the number of weeks to get reading time. Multiply the number of hours by the number of minutes in an hour to get minutes.

8 0
3 years ago
Suppose that you are responsible for making arrangements for a business convention and that you have been charged with choosing
REY [17]
Got a zero sum of what I was going to do get it back better than I did weewweee
8 0
3 years ago
A major retail clothing store is interested in estimating the difference in mean monthly purchases by customers who use the stor
mixer [17]

Answer:

Critical value is t = 1.9901

Step-by-step explanation:

We are given the results of the sampling :

                                     In-House Credit Card                National Credit Card                    <u>Sample Size</u> :                              32                                                    50

<u>Mean Monthly Purchases </u>:      $45.67                                            $39.87

<u>Standard Deviation </u>:                $10.90                                             $12.47

Also, the managers wished to test whether there is a statistical difference in the mean monthly purchases by customers using the two types of credit cards, using a significance level α of 0.05.

<em>Firstly, we will specify our null and alternate hypothesis;</em>

Let \mu_1 = Mean Monthly Purchases of In-House Credit Card

     \mu_2 = Mean Monthly purchases of National Credit Card

So, Null Hypothesis, H_0 : \mu_1-\mu_2 = 0  {means that there is no difference in the mean monthly purchases by customers using the two types of credit cards}

Alternate Hypothesis, H_0 : \mu_1-\mu_2\neq 0  {means that there is statistical difference in the mean monthly purchases by customers using the two types of credit cards}

The test statistics that will be used here is <u>Two-sample t-test statistics</u>;

              T.S. = \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  ~ t_n___1+n_2-_2

where, \bar X_1 = Sample mean Purchases of In-House Credit Card = $45.67

           \bar X_2 = Sample mean Purchases of National Credit Card = $39.87

            s_p = pooled variance

            n_1 = In-house credit card sample = 32

            n_2 = National credit card sample = 50

So, degree of freedom of t-value here is (32 + 50 - 2) = 80

Now, at 0.05 significance level, t table gives critical value of t = 1.9901 at 80 degree of freedom.

<em>Therefore, the critical value assuming the population standard deviations are not known but that the populations are normally distributed with equal variances is t = 1.9901.</em>

4 0
3 years ago
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