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denis23 [38]
3 years ago
8

Numbers that are greater than 5 and less than 5.75

Mathematics
2 answers:
Goshia [24]3 years ago
5 0
The easy way to think about this is what number comes between 5 and 7? The answer is 6 (but we have to consider that it's negative in this case.) So the answer is -6 Another way to look at it is with a number line (not to "Which number is greater than -7 and less than -5"? scale.)<===(-7)==(-6)==(-5)==(-3)==(-2)==(-1)==(0)==(1)==>Notice how -6 comes between the two numbers. -6 is larger than -7 (it's "less negative" -- "Which number is greater than -7 and less than -5"? closer to zero) -6 is less than -5 (it's "more negative" -- further away from zero)
ludmilkaskok [199]3 years ago
4 0
5.1,5.2,5.3,5.4,5.5,5.6
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Sick-leave time used by employees of a firm in a course of one month has approximately normal distribution, with a mean of 200 h
Usimov [2.4K]

Answer:

a)0.62% probability that total sick leave for next month will be less than 150 hours.

b) 225.6 hours should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 200, \sigma = \sqrt{400} = 20

a.Find the probability that total sick leave for next month will be less than 150 hours.

This probability is the pvalue of Z when X = 150. So:

Z = \frac{X - \mu}{\sigma}

Z = \frac{150 - 200}{20}

Z = -2.5

Z = -2.5 has a pvalue of 0.0062.

So there is a 0.62% probability that total sick leave for next month will be less than 150 hours.

b.In planning schedules for next month, how much time should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

This is the value of X when Z has a pvalue of 0.90. So Z = 1.28

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 200}{20}

X - 200 = 20*1.28

X = 225.6

225.6 hours should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

the 15 is the slope, so that is the number that has to be multiplied by. The 250 is an additional fee that doesn't change, so it's just added on.

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