1 mile = about 1 1/3 km because 8/6 = 1 1/3
so 28 times 1 1/3 = 37 1/3 (first answer)
42 / 6 = 7
7 miles are in 42 km (2nd answer)
Answer:
31 inches. Add all the sides together. The height is not needed. 6.5+13.5+4+7=31 inches.
Step-by-step explanation:
f(-1) = -11 and f(3) = -3 . these functions are true .
What does a math function mean?
- A relationship between a group of inputs and one output each is referred to as a function.
- A function is an association between inputs in which each input is connected to precisely one output.
- A domain, codomain, or range exists for every function. f(x), where x is the input, is a common way to refer to a function.
- In mathematics, a function is an expression, rule, or law that establishes the relationship between two variables (the dependent variable).
given function f(x) = 2x - 9
f(-1) = -11 ⇒ x = -1 put in function
f( -1 ) = 2 * -1 - 9 ⇒ - 11
f(2) = 5 ⇒ x = 2 put in function
f( 2 ) = 2 * 5 - 9 = 1
f(3) = -3 ⇒ x = 3 put in function
f ( 3 ) = 2 * 3 - 9 = -3
f(-3) = 15 ⇒ x = -3 put in function
f( -3) = 2 * -3 - 9 = - 15
Learn more about function
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Wow !
OK. The line-up on the bench has two "zones" ...
-- One zone, consisting of exactly two people, the teacher and the difficult student.
Their identities don't change, and their arrangement doesn't change.
-- The other zone, consisting of the other 9 students.
They can line up in any possible way.
How many ways can you line up 9 students ?
The first one can be any one of 9. For each of these . . .
The second one can be any one of the remaining 8. For each of these . . .
The third one can be any one of the remaining 7. For each of these . . .
The fourth one can be any one of the remaining 6. For each of these . . .
The fifth one can be any one of the remaining 5. For each of these . . .
The sixth one can be any one of the remaining 4. For each of these . . .
The seventh one can be any one of the remaining 3. For each of these . . .
The eighth one can be either of the remaining 2. For each of these . . .
The ninth one must be the only one remaining student.
The total number of possible line-ups is
(9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1) = 9! = 362,880 .
But wait ! We're not done yet !
For each possible line-up, the teacher and the difficult student can sit
-- On the left end,
-- Between the 1st and 2nd students in the lineup,
-- Between the 2nd and 3rd students in the lineup,
-- Between the 3rd and 4th students in the lineup,
-- Between the 4th and 5th students in the lineup,
-- Between the 5th and 6th students in the lineup,
-- Between the 6th and 7th students in the lineup,
-- Between the 7th and 8th students in the lineup,
-- Between the 8th and 9th students in the lineup,
-- On the right end.
That's 10 different places to put the teacher and the difficult student,
in EACH possible line-up of the other 9 .
So the total total number of ways to do this is
(362,880) x (10) = 3,628,800 ways.
If they sit a different way at every game, the class can see a bunch of games
without duplicating their seating arrangement !
