All categories

2 years ago

I WILL MARK! PLS ANSWER THIS.

Mathematics

2 answers:

babunello [35]2 years ago

7 0

Answer:

From least (top) to greatest (bottom):

-3.5--in between -4 and -3

-3--on the -3 line

-2 1/5--in between the -3 and the -2

-2--on the -2 line

2.5--in between 2 and 3

love history [14]2 years ago

6 0

Answer:

-3.5 -3, -2 1/2, -2, 2.5

Step-by-step explanation:

You might be interested in

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago

What is the distance between (4,2) and (-1,-3)

Sati [7]

<h2>Solving for the Distance between two Points</h2><h3>Answer:</h3>

$5 \sqrt{2}$ or $7.071$

<h3>Step-by-step explanation:</h3>

<em>Please refer to my answer from this Question to know more about distances between two points: <u>brainly.com/question/24629826</u></em>

Given:

$(4,2)$

$(-1,-3)$

Solving for the Distance:

$\sqrt{(4-(-1))^2 +(2 -(-3))^2} \\ \sqrt{(4 +1)^2 +(2 +3)^2} \\ \sqrt{5^2 +5^2} \\ \sqrt{25 +25} \\ \sqrt{50} \\ \sqrt{25 \cdot 2} \\ 5 \sqrt{2}$

<u>Note:</u>

$5 \sqrt{2} \approx 7.071$

4 0

3 years ago

Help please no bias answers

notka56 [123]

Answer:

882 square inches

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Michael is constructing a circle circumscribed about a triangle. he has partially completed the construction. what should be his

earnstyle [38]

Answer:

Connect the arcs to make a perpendicular bisector

6 0

1 year ago

Select the function that's represented in the graph. Question 5 options: A) ƒ(x) = x2 – 3 B) ƒ(x) = –1∕2x2 – 3 C) ƒ(x) = –x2 – 3

Neporo4naja [7]

Answer:

Step-by-step explanation:

hello,

because of the end behaviour the constant in $x^2$ should be positive so we have a) or d)

f(0)=-3 in both cases

for A) f(x)=

$x^2-3=(x-\sqrt{3})(x+\sqrt{3})$

so f(x)=0 for $x=\sqrt{3} \ or \ x = -\sqrt{3}$

so the correct answer is A)

hope this helps

3 0

3 years ago