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SVETLANKA909090 [29]
3 years ago
15

Which monomials are perfect squares? Select THREE options:

Mathematics
2 answers:
lions [1.4K]3 years ago
8 0
Answer:
Step-by-step explanation:
Let's check all the monomials

Here 6 is not square digit, hence this monomial is not a perfect square.

Here 9 is a square digit and the power of x i.e. 8 is multiple of 2 .
Hence, this monomial is a perfect square.

Here 16 is a square digit but the power of x i.e.9 is not multiple of 2 .
Hence, this monomial is not a perfect square.

Here 25 is a square digit and the power of x i.e. 12 is multiple of 2 .
Hence, this monomial is a perfect square.

Here 36 is a square digit and the power of x i.e.16 is multiple of 2 .
Hence, this monomial is a perfect square.
levacccp [35]3 years ago
7 0

Answer:

e djdjd E. JDJDHDHD E hdjdjdjdbdb Eeeeeee

Step-by-step explanation:

find the answEr

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If you get paid $15 and hour, how much would time and a half be?
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Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.
Zigmanuir [339]
The mean is the average.
So, to find the mean you want o add up all of the numbers and then divide by the number of numbers.

49 + 49 + 54 + 55 + 52 + 49 + 575 = 363
363 / 7 = 51.85
Rounded to 52

For the median you want o line all of your number up from least to greatest and then find the middle number.

49,49,49,52,54,55,55

Your median is 52

The mode is the number that is listed most often

49 is listed 3 times
54 is listed 1 time
52 is listed 1 time
55 is listed 2 times

So, your mode is 49




4 0
3 years ago
You and your soccer team are interested in buying jerseys. The price of each jersey is $50. If you buy 4 jerseys, you will get 1
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Maths Problem. I can't quite explain it, could you help please? Thanks for every good answer. All shown on the picture :)
Nimfa-mama [501]

This is something you would do through trial and error. At least, that's the approach I took. I'm not sure if there is any algorithm to solve. The solution I got is shown in the attached image below. There are probably other solutions possible. The trick is to keep each number separate but not too far away so that the other numbers to be filled in later don't get too crowded to their neighbor.

Side note: any mirror copy of what I posted would work as well since you can flip the page around and it's effectively the same solution.

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