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3 years ago

15.

Mathematics

1 answer:

ale4655 [162]3 years ago

5 0

Answer:

y=10/x

Step-by-step explanation:

Y=k/x

Y=2 & x=5 implies k=10

Hence, y=10/x is the desired equation of the hyperbola

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Answer:

The equation is and y = 2 , x = 5 the value of k is 10 .

Step-by-step explanation:

As given

y varies inversely with x.

Where k is the constant of proportionality .

Thus the equation for the inverse variation .

As given

y = 2 when x = 5

Put all the values in the equation .

k = 2 × 5

k = 10

Thus the constant of variation is 10 .

Therefore the equation is and when y = 2 , x = 5 value of k is 10 .

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Explanation:

varies inversely with

⇒

∝

∴

gives

⇒

Answer link

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Y varies inversely with x means, y=k\x where x is the constant of variation saying that 2=k\5 and gives k=10 y=10\x would be the equation for any x

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The answer is y=10/x

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Answer:

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Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of $2\hat{i}-6\hat{k}\text{ m/s}$ . If a cyclist travels through the hail at $10\hat{i} \text{ m/s}$ .

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

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The velocity of the hailstone falls is $V_h=2\hat{i}-6\hat{k}\text{ m/s}$

The velocity of the cyclist travels through the hail is $V_c=10\hat{i} \text{ m/s}$

The velocity of the hail relative to the cyclist is given by,

$V_{hc}=V_h-V_c$

Substitute the value in the formula,

$V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}$

$V_{hc}=-8\hat{i}-6\hat{k}$

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Now, The angle of hails falling relative to the cyclist is given by

$\theta = \tan^{-1}(\frac{-6}{-8})$

$\theta = \tan^{-1}(\frac{3}{4})$

$\theta = 36.86^\circ$

So, The angle at which hailstones falling relative to the cyclist is $\theta = 36.86^\circ$

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