A1 + a2 + a3 + a4 + a5

Katyanochek1 [597]

Could you please show the question so I can try to answer it

4 0

2 years ago

The net of a square pyramid is shown below: Net of a square pyramid showing 4 triangles and the square base. The square base has

Neko [114]

Given:

The dimensions:

Square pyramid

Square base: 2x2

1 out of 4 triangles: 1/2x2x5

4 triangles: 2x2x5

To find:

The SURFACE AREA of the square pyramid

Find answer:

Step 1

Find the area of the square base -

Square base:

SA = L x W

= 2 x 2

= 4

<em>The surface area of the square is 4 square inches</em>

Step 2

Find the area of the 4 Triangles:

We will use a different formula here, to find 1 triangle, we will have to do:

$SA = \frac{1}{2} *B*H$

To find 2 triangles, we will do:

$SA = B*H$

But to find 4 triangles in just 1 step, we will do:

$SA=2*B*H$

Let's do it!

$SA = 2*2*5\\=2*10\\=20$

<em>The surface area of the 4 triangles are 20 square inches</em>

Step 3

Add answers to get FINAL ANSWER

Easy!

20+4=24

<h2>Hence, the Surface Area of the Square Pyramid is 24 square inches</h2>

4 0

1 year ago

Help it’s slope idk how to do it

Over [174]

a. $\boxed{y-602=\frac{2}{3}(x-3)}$

b. For every month the pine tree grows about 0.67 inches.

c. <em> </em>It represents the height of the tree at the moment Ariel started to record the heights.

<h2>Explanation:</h2>

In this exercise we have that in July Ariel recorded the height of a pine tree and how quickly it was expected to grow in next several months. From the Table, we can get the following points:

$P_{1}(3,602) \\ \\ P_{2}(6,604) \\ \\ P_{3}(q,606) \\ \\ P_{4}(12,608)$

It is obvious that this problem follows a linear equation, so our goal is to find the equation that matches the Table.

The point slope form of the equation of a line is:

$y-y_{1}=m(x-x_{1}) \\ \\ Where: \\ \\ m:Slope \\ \\ (x_{1}, y_{1}):A \ point \ on \ the \ line$

Finding (m):

$Using: \\ \\ P_{1}(x_{1},y_{1}) \rightarrow P_{1}(3,602) \\ \\ P_{2}(x_{2}, y_{2}) \rightarrow P_{2}(6,604) \\ \\ m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{604-602}{6-3} \\ \\ m=\frac{2}{3}$

Finally, the equation of the line is:

$(x_{1}, y_{1}) \rightarrow (3,602) \\ \\ \boxed{y-602=\frac{2}{3}(x-3)}$

In this case, we have that:

The x-axis represents the <em>Number of Months </em>the pine tree was expected to grow.
The y-axis represents the <em>Height of the Tree </em>in inches.

Since the slope o a line is:

$Slope=\frac{Change \ in \ y}{Change \ in \ x}=\frac{2}{3}$

Then, this means that<em> every three months the pine tree grows two inches, </em><em>or </em><em>for every month the pine tree grows about 0.67 inches.</em>

The y-intercept can be found setting $x=0$ . So, from our equation: