Answer:
A section of wall is being framed. A model of the framing work is shown below. Vertical and parallel lines c, d, and e are cut by diagonal transversal b. The uppercase right angle formed by the intersection of lines b and c is angle A. The uppercase left angle formed by the intersection of lines d and b is 125 degrees. Which best describes the relationship between the 125° angle and angle A? They are same side interior angles. Angle A measures 55°. They are alternate interior angles. Angle A measures 125°. They are vertical angles. Angle A measures 125°. They are corresponding angles. Angle A measures 55°.
angle D
Answer:
x = -8/3
Step-by-step explanation:
1/2x+3 = 2/3+1
Combine like terms
1/2x+3 = 2/3 + 3/3
1/2x + 3 = 5/3
Subtract 3 from each side
1/2x + 3-3 = 5/3 - 3
1/2x = 5/3 - 9/3
1/2x = -4/3
Multiply each side by 2
1/2x *2 = -4/3*2
x = -8/3
Answer: 180= 38+(17x+1)+(3x+1), All the angles in a triangle add up to 180 degrees, so I made all the add measures equal to 180 degrees.
Just solve that equation to find x. Then used then plug in the x value to (17x+1). After you solve that put it equal to 2y to solve for y.
So the y equation would look like: 2y=(17x+1) (but you would have solved for x and then plugged it in to the equation)
If you need help solving or have any questions let me know!
Answer: After about 9.03 hours the temperature first reach 82 degrees.
Step-by-step explanation:
The sinusoidal function is given by :
![y=A\sin[\omega(x-\alpha)]+C](https://tex.z-dn.net/?f=y%3DA%5Csin%5B%5Comega%28x-%5Calpha%29%5D%2BC)
where, A = amplitude; 
, α= phase shift on the Y-axis and C = midline.
As per given,
Average daily temperature= 
[midline is average of upper and lower limit.]
A= 97-85 = 12
Phase shift: 
Period = 24 hours;
Substitute all values in sinusoidal function, we get
![y=12\sin[\dfrac{\pi}{12}(x-10)]+85](https://tex.z-dn.net/?f=y%3D12%5Csin%5B%5Cdfrac%7B%5Cpi%7D%7B12%7D%28x-10%29%5D%2B85)
Put y= 82, we get
![82=12\sin[\dfrac{\pi}{12}(x-10)]+85\\\\\Rightarrow\ -3= 12\sin[\dfrac{\pi}{12}(x-10)]\\\\=\dfrac{-1}{4}= \sin[\dfrac{\pi}{12}(x-10)]\\\\\Rightarrow\ \dfrac{\pi}{12}(x-10)=\sin^{-1}(\dfrac{-1}{4})\\\\\Rightarrow\ x-10=\dfrac{12}{\pi}(\sin^{-1}(\dfrac{-1}{4}))\\\\\Rightarrow\ x=\dfrac{12}{\pi}(\sin^{-1}(\dfrac{-1}{4}))+10\\\Rightarrow\ x\approx9.03](https://tex.z-dn.net/?f=82%3D12%5Csin%5B%5Cdfrac%7B%5Cpi%7D%7B12%7D%28x-10%29%5D%2B85%5C%5C%5C%5C%5CRightarrow%5C%20-3%3D%2012%5Csin%5B%5Cdfrac%7B%5Cpi%7D%7B12%7D%28x-10%29%5D%5C%5C%5C%5C%3D%5Cdfrac%7B-1%7D%7B4%7D%3D%20%5Csin%5B%5Cdfrac%7B%5Cpi%7D%7B12%7D%28x-10%29%5D%5C%5C%5C%5C%5CRightarrow%5C%20%5Cdfrac%7B%5Cpi%7D%7B12%7D%28x-10%29%3D%5Csin%5E%7B-1%7D%28%5Cdfrac%7B-1%7D%7B4%7D%29%5C%5C%5C%5C%5CRightarrow%5C%20x-10%3D%5Cdfrac%7B12%7D%7B%5Cpi%7D%28%5Csin%5E%7B-1%7D%28%5Cdfrac%7B-1%7D%7B4%7D%29%29%5C%5C%5C%5C%5CRightarrow%5C%20x%3D%5Cdfrac%7B12%7D%7B%5Cpi%7D%28%5Csin%5E%7B-1%7D%28%5Cdfrac%7B-1%7D%7B4%7D%29%29%2B10%5C%5C%5CRightarrow%5C%20x%5Capprox9.03)
Hence, After about 9.03 hours the temperature first reach 82 degrees.
Answer:
answer is yesterday was thrusdays
