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stira [4]
3 years ago
8

A ball is dropped from a height of 5ft and bounces to 60% of I?ts previous height in each subsequent bounce

Mathematics
1 answer:
Gelneren [198K]3 years ago
7 0

Answer:

Im assuming youre trying to answer what is the 60% height, it would be 3ft

Step-by-step explanation:


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NO LINKS!!! Please help fill in the blanks. Part 11a
Lorico [155]

Answer:

  see attached

Step-by-step explanation:

Here's your worksheet with the blanks filled.

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Of course, you know these log relations:

  log(a^b) = b·log(a) . . . . . power property

  log(a/b) = log(a) -log(b) . . . . . quotient property

  log(x) = log(y)   ⇔   x = y . . . . . . . . . equality property

4 0
2 years ago
What is the mean, median, mode, and range of 8, 35, 10, 12, 14?
Ivan

answer:

mean: 15.8

median: 12

mode: no mode

range: 27

step-by-step explanation:

  • first know how to find each of the above and what they are
  • mean = (avg) add all the numbers, then divide by the number of numbers
  • median = the middle number from increasing order
  • mode = the one that repeats the most
  • range = the difference between the largest and smallest number

8, 35, 10, 12, 14

<u>mean</u>

8 + 35 + 10 + 12 + 14 = 79

  • there are five numbers

79 / 5 = 15.8

<u>median</u>

  • put them from smallest to largest

8, 10, 12, 14, 35

  • 12 is the median OR the middle number

<u>mode</u>

  • no number repeat, so no mode

<u>range</u>

35 - 8 = 27

3 0
3 years ago
Is x-3/5 = N and N = 6, what is the value of x?
scZoUnD [109]

Answer:

x = 33/5

Step-by-step explanation:

x - 3/5 = n.......n = 6

so we sub

x - 3/5 = 6......add 3/5 to both sides

x = 6 + 3/5...convert using common denominator of 5

x = 30/5 + 3/5

x = 33/5 <===

check...

x - 3/5 = 6

33/5 - 3/5 = 6

30/5 = 6

6 = 6 (correct)...so it checks out

5 0
3 years ago
Read 2 more answers
I REALLY NEED HELP PLZ :(((((
liberstina [14]

Answer:

Where is the picture?

Step-by-step explanation:

5 0
3 years ago
How many words of five letters can be created that start with the letter T, contain 2 other consonats and end with 2 vowels? Not
Jet001 [13]

If we're only counting 5 vowels (A, E, I, O, U) and 20 consonants (everything else, minus T), then there are

\dbinom52=\dfrac{5!}{2!(5-2)!}=10

ways of picking the vowels, and

\dbinom{20}2=\dfrac{20!}{2!(20-2)!}=190

ways of picking the consonants.

We want the word to start with T, and we'll allow any arrangement of the other 4 letters, so that the total number of words is

4!\dbinom52\dbinom{20}2=\boxed{45,600}

Keep in mind that this means words like TRIES and TIRES are treated as different.

8 0
3 years ago
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