Step-by-step explanation:
Solution:
Here,
Volume of the tank=539 litres
=539×1000cm^3=539000cm^3
Height=1.4×100cm=140cm
Let the radius of the base be r cm
Then,
22/7×r^2×140=539000
or,r^2=539000×7/22×140
or,r^2=1225
or,r=35 cm
So,
Area of base=pie r^2
=22/7×35^2
=3850 cm^2
<em>Keep</em><em> </em><em>smiling </em><em>and</em><em> </em><em>hope</em><em> </em><em>u</em><em> </em><em>r</em><em> </em><em>satisfied </em><em>with</em><em> </em><em>my</em><em> </em><em>answer</em><em>.</em><em>Have</em><em> </em><em>a</em><em> </em><em>good</em><em> </em><em>day</em><em> </em><em>:</em><em>)</em>
Answer:
she started with 75 and puts in 15 dollars every week. meaning that she initially deposited $75
Answer:
20m
Step-by-step explanation:
Area of garden = 400m²
Area = L² = 400m²
L = √400m²
L = 20m
$46
heater and insurance for each sheep subtracted from the total amount leaves $740. Then divided by the amount of sheep equals $46!
Hope I helped!
Answer:
Step-by-step explanation:
The genral form of a complex number in rectangular plane is expressed as z = x+iy
In polar coordinate, z =rcos ∅+irsin∅ where;
r is the modulus = √x²+y²
∅ is teh argument = arctan y/x
Given thr complex number z = 6+6√(3)i
r = √6²+(6√3)²
r = √36+108
r = √144
r = 12
∅ = arctan 6√3/6
∅ = arctan √3
∅ = 60°
In polar form, z = 12(cos60°+isin60°)
z = 12(cosπ/3+isinπ/3)
To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)
z^1/4 = 12^1/4(cosπ/12+isinπ/12)
When n = 1;
z1 = 12^1/4(cosπ/3+isinn/3)
z1 = 12^1/4cis(π/3)
when n = 2;
z2 = 12^1/4(cos2π/3+isin2π/3)
z2 = 12^1/4cis(2π/3)
when n = 3;
z2 = 12^1/4(cosπ+isinπ)
z2 = 12^1/4cis(π)
when n = 4;
z2 = 12^1/4(cos4π/3+isin4π/3)
z2 = 12^1/4cis(4π/3)