Answer:
Step-by-step explanation:
11) First write in decreasing exponential terms and fill in blanks with zeros.
Our goal is to eliminate all term in the dividend by subtraction
________________
2v - 2 | 2v³ - 16v² + 0v + 13
we see that 2v needs to be multiplied by 1v² to eliminate the first term
<u> v² </u>
2v - 2 | 2v³ - 16v² + 0v + 13
<u>- (2v³ - 2v²)</u>
0 - 14v²
multiply your estimate by your divisor and subtract from the dividend.
bring down the next term and repeat.
<u> v² -7v </u>
2v - 2 | 2v³ - 16v² + 0v + 13
<u>- (2v³ - 2v²)</u>
0 - 14v² + 0v
<u>-(-14v² + 14v)</u>
- 14v
repeat again
<u />
<u> v² - 7v - 7 </u>
2v - 2 | 2v³ - 16v² + 0v + 13
<u>- (2v³ - 2v²)</u>
0 - 14v² + 0v
<u>-(-14v² + 14v)</u>
- 14v + 13
<u>-(-14v + 14)</u>
-1
and remainder gets put over the divisor and appended
v² - 7v - 7 - 1/(2v - 2)
13) Same process
<u> </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u> 8a² </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u>-(40a³ + 8a²)</u>
-20a² - 39a
<u> 8a² - 4a </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u>-(40a³ + 8a²)</u>
-20a² - 39a
-(-<u>20a² - 4a)</u>
-35a - 5
<u> 8a² - 4a - 7 </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u>-(40a³ + 8a²)</u>
-20a² - 39a
-(<u>20a² - 4a)</u>
-35a - 5
-<u>(-35a - 7)</u>
2
8a² - 4a - 7 + 2/(5a + 1)
Answer:
sqrt 50
Step-by-step explanation:
First of all this is a square so if AB = 5, then AD is also 5.
Let's get rid of the other triangle and only focus on triangle ABD.
Using Pythagorean theorem we are able to solve this problem.
The Pythagorean Theorem basically states that:
a^2 + b^2 = c^2
Where a and b are the legs and c is the hypotenuse, aka the thing that we are trying to solve for right now.
Substitute these numbers in: 5^2 + 5+2 = c^2
Solve: 50 = c^2
c= sqrt 50
^ and that is our answer!
Answer:
It is a vertical line
Step-by-step explanation:
the equation will be in the form of Ax=C hence we can make X the subject of the formula giving

9514 1404 393
Answer:
643.72 m²
Step-by-step explanation:
The area is the sum of the areas of the parts. The figure can be divided into a triangle and a semicircle.
The formula for the area of the triangle is ...
A = 1/2bh
For the given base of 28 m and height of 24 m, the area is ...
A = 1/2(28 m)(24 m) = 336 m²
__
The area of a semicircle is given by the formula ...
A = (π/8)d² . . . . for diameter d
The given diameter is 28 m, so the area is about ...
A = (3.14/8)(28 m)² = 307.72 m²
__
Then the total area of the figure is ...
total area = triangle area + semicircle area
total area = 336 m² +307.72 m² = 643.72 m²