Point P has coordinates (1,3). Point Q has coordinates (25,10). How long is segment PQ?

1. Charlene makes $10 per hour babysitting and $5 per hour gardening. This week, she wants to make at least $80.

Lady_Fox [76]

Answer:

Step-by-step explanation:

Well is she wanted to make $80 “b” she would have to garden for 16 hours to make a maximum of $80

“C” if she wanted to make it out of babysitting she would have to work the same for 8 hours if she babysit

Workout : b part = 10+10+10+10+10+10+10+10 Key:10=2

:c part = 20+20+20+20. Key:20=2

Sorry I didn’t do a but just add all the things above and u get your answer

4 0

2 years ago

1) In Tara's math class, each student made up a number pattern for classmates to identify. These are the numbers that Tara wrote

pav-90 [236]

Answer:

TBH its a Link of this its call pdf and it tell yuu all your answer

Step-by-step explanation:

5 0

2 years ago

The function y = 2x2 + 4x - 6 is graphed.

lys-0071 [83]

Answer:

2 for the first drop down

-3 and 1 for the second

Step-by-step explanation:

no u

7 0

3 years ago

Is0.85 a fraction mixed number or a decimal

mamaluj [8]

0.85 is a decimal //////

6 0

3 years ago

Teen obesity:

Law Incorporation [45]

Answer:

95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

Step-by-step explanation:

We are given that 15% of a random sample of 300 U.S. public high school students were obese.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample % of U.S. public high school students who were obese = 15%

n = sample of U.S. public high school students = 300

p = population percentage of all U.S. public high school students

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.15-1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } }$ , $0.15+1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } }$ ]

= [0.110 , 0.190]

Therefore, 95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

6 0

3 years ago