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kiruha [24]
3 years ago
5

-1/6 + 2/3 (9 - 3/4) - 1/2 I’m confused if someone can help

Mathematics
1 answer:
emmainna [20.7K]3 years ago
7 0

Answer:

4.83333333333

Step-by-step explanation:

I'm sorry if that is wrong but I believe it is right

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3 years ago
Lucas has a bag that contains 11
Komok [63]

Answer:

3667 times

Step-by-step explanation:

5 0
3 years ago
There are bricks of silver and bricks of gold. When 5 silver bricks and 2 gold bricks are placed on a scale, the weight is 119 o
Illusion [34]

Answer:

The weight of one gold brick is 15 ounces and the weight of one silver brick is 22 ounces.

Step-by-step explanation:

Given,

Weight of 5 silver bricks and 2 gold bricks = 119 ounces.

And Weight of 4 silver bricks and 11 gold bricks = 302 ounces.

We have to find out weight of each type of brick.

Solution,

Let the weight of 1 silver brick be x.

And the weight of 1 gold brick be y.

Since the weight of 5 silver bricks and 2 gold bricks is 119 ounces.

So we can frame it in equation as;

5x+2y=119\ \ \ \ \ equation\ 1

Again,

The weight of 4 silver bricks and 11 gold bricks is 302 ounces.

So we can frame it in equation as;

4x+11y=302\ \ \ \ \ equation\ 2

Now, multiplying equation 1 by 4 and equation 2 by 5 we get;

4(5x+2y)=119\times4\\\\20x+8y=476\ \ \ \ \ equation\ 3

5(4x+11y)=302\times5\\\\20x+55y=1510\ \ \ equation\ 4

Now subtract equation 3 from equation 4, we get;

(20x+55y)-(20x+8y)=1510-476\\\\20x+55y-20x-8y=1034\\\\47y=1034\\\\y=\frac{1034}{47}\\\\y=22

On substituting yhe value of y in equation 1, we get;

5x+2y=119\\\\5x+2\times22=119\\\\5x+44=119\\\\5x=119-44=75\\\\x=\frac{75}{5}\\\\x=15

Thus the weight of one gold brick is 15 ounces and the weight of one silver brick is 22 ounces.

4 0
3 years ago
Point (17,18) is located in quadrant​
Nadusha1986 [10]

Answer:

25

Step-by-step explanation:

add 7+ to the quadrant to 18+

7 0
2 years ago
Read 2 more answers
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