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AVprozaik [17]
3 years ago
8

If the initial velocity stays the same, but the height the projectile is launched from changes , how would the amount of time ch

ange that it takes for the projectile to reach its maximum height? How would its maximum height change?
Mathematics
1 answer:
pickupchik [31]3 years ago
6 0

Answer:

Part A

The height to which the projectile reaches is given by the following formula;

\Delta y = y-y_0 = v_{0y} \times t-\dfrac{1}{2} \times g \times t^2

Where;

v_{0y} = The initial velocity of the projectile = Stays the same

y = The height the projectile reaches

y₀ = The height from which the projectile is launched

g = The acceleration due to gravity

t = The time taken

Given that the projectile has the same initial velocity, the variation of Δy with time, 't', will be the same when the project is launched from a different height, and the time change that it takes for the projectile to reach the maximum height will be the same for the previous launch height

Part B

From the change in eight of the projectile, Δy = y - y₀, the maximum height reached, 'y', is therefore given as follows;

y = Δy + y₀

The maximum height will increase by 'y₀', where 'y₀' is the difference between new height and the previous height, y_i

That is, if y₀ > y_i, the maximum height reached increases and if y₀ < y_i, y₀ will be added as y = Δy - y₀ and the maximum height reached decreases

Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

y = 16x²

you put the x values one after the other in place of x and do the calculations.

x = -4

y = 16×(-4)² = 16×16 = 256

x = -3

y = 16×(-3)² = 16×9 = 144

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x = 0.5

y = 16×0.5² = 16×0.25 = 4

x = 1

y = 16×1² = 16×1 = 16

and so on.

36, 64, 100, 144, 256

as you can see, the y values are the same for the positive and the negative values.

because squaring a negative number is the same as squaring the same positive number. that is, because (if you remember) squaring something means to multiply that something with itself. and minus multiplied by minus is plus, as plus multiplied by plus is plus.

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3 years ago
What is the vertex of the graph of the following equation? y = x^2 + 2x-3
ExtremeBDS [4]

Answer:

vertex = (- 1, - 4 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = - \frac{b}{2a}

y = x² + 2x - 3 ← is in standard form

with a = 1, b = 2 , then

x = - \frac{2}{2} = - 1

Substitute x = - 1 into the equation for corresponding value of y

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Consider the following game, played with three standard six-sided dice. If the player ends with all three dice showing the same
ddd [48]

Answer:

a

 P(A) =  \frac{1}{36}

b

P(B) = \frac{15}{36}

c

P(U) = \frac{11}{36}

Step-by-step explanation:

From the question we are told that

   The  number of dice is  n  =  3

Generally  for all three dice to show the same number the second and the third dice must have the same outcome  as the outcome of the first dice.

This means that the number of outcome the first die can  have is  6  (6 sides), the number of outcome which the second and the third dice can have is  1 (they must match the first )

So the probability that all three dice show the same number on the first roll is mathematically represented as

      P(A) =  \frac{6}{6} * \frac{1}{6} *  \frac{1}{6}

=>   P(A) =  \frac{1}{36}

Generally for two of the three dice show the same number after the first roll then the number of outcome for  one of the  dice would be is  6 , the number of outcome for another one must be   1(i.e it must match the first ) , the number of outcome for the remaining one must be   5 (i.e it can show any of the remaining  5  sides which the first and second dice are not showing )

Now the number of ways of selecting this 2 dice that show the same number from the 3 dice is mathematically represented as

     N  =  ^3C_2

Here C stands for combination

So

      N  =  ^3C_2  = 6

So the probability that exactly two of the three dice show the same number after the first roll is mathematically represented as  

      P(B) = N   \frac{1}{6} *  \frac{5}{6}

=>  P(B) = \frac{15}{36}

Generally from the question we are told that if two dice match, the player re-rolls the die that does not match.

Now the probability that  the die that did not match the first  time will match the second time is

     P(E ) =  \frac{1}{6}

Generally if that one die does not show the same number in the second round , the probability that it will match  in the third round is

    P(R) =  \frac{5}{6} *  \frac{1}{6}

Generally the probability that he wins (i.e when all three are showing the same number ) and  exactly two is showing the same number is mathematically represented as

       P(K) =  P(E)* P(B) + P(R)* P(B)

=>    P(K) =  \frac{1}{6} * \frac{15}{36}  +  \frac{5}{6} *  \frac{1}{6} * \frac{15}{36}

=>  P(K)= \frac{165}{1296}

So the probability that the player wins, conditioned on exactly two of the three dice showing the same number after the first roll is mathematically represented as  

    P(U) =  \frac{\frac{165}{1296}}{\frac{15}{36} }

=>  P(U) = \frac{11}{36}

     

 

6 0
3 years ago
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