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Leto [7]
3 years ago
15

Determine the slope for the equation.

Mathematics
2 answers:
posledela3 years ago
6 0

Answer:

slope = \frac{6}{5}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{6}{5} x - 4 ← is in slope- intercept form

with slope m = \frac{6}{5}

Ivanshal [37]3 years ago
5 0

Answer:

6/5

Step-by-step explanation:

<em>this </em><em>equation</em><em> </em><em>is </em><em>already</em><em> </em><em>in </em><em>the </em><em>slope</em><em> </em><em>intercept</em><em> form</em><em>,</em><em> meaning</em><em> </em><em>the </em><em>slope</em><em> (</em><em>gradient</em><em>)</em><em>is </em><em>the </em><em>coefficient</em><em> </em><em>of </em><em>x(</em><em> </em><em>the </em><em>number</em><em> </em><em>before</em><em> </em><em>x)</em><em>.</em><em> </em><em>in </em><em>this </em><em>case </em><em>it's </em><em>6</em><em>/</em><em>5</em><em>.</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

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Maksim231197 [3]

Answer:

28.26 cm^2

Step-by-step explanation:

The area of the quarter circle is the area of the circle / 4. Thus, the area is \frac{\pi r^2}{4} = \frac{3.14*6^2}{4} = 28.26 square centimeters

8 0
3 years ago
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Kristen read a total of 20 books over 4 months. After belonging to the book club for 5
KATRIN_1 [288]

Answer:

25

Step-by-step explanation:

20 books in 4 months is 5 books in 1 month.

20÷4=5

4÷4=1

1×5=5

5×5=25

7 0
3 years ago
Solve the equation for x by graphing.<br><br> 2^x - 4 = -4^x + 4
lapo4ka [179]
X~1.25. All you have to do is graph the function and see where the graph crosses the x-axis.
8 0
3 years ago
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Square root of 5u+2 = square root of 3u+14
alina1380 [7]
Sqrt(5u + 2) = sqrt(3u + 14)
Square both sides to clear the square root.
5u + 2 = 3u + 14
subtract 3u from both siides
2u + 2 = 14
subtract 2 from both sides
2u = 12
divide both sides by 2
u = 6
When you square a square root you MUST check the solution.
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8 0
3 years ago
Please help me with these
Alex Ar [27]
When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) \lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
= \frac{-5}{-25}
= \frac{1}{5}

<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}
= \frac{1}{5}

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
8 0
3 years ago
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