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borishaifa [10]

3 years ago

5

If the value of a is negative in the quadratic function, f(x) = ax + bx + C, and the vertex is at (13, -2), then how many x-inte

rcepts will the graph have?
A. can't be determined
В. 0
C. 1
D. 2

1 answer:

mash [69]3 years ago

6 0

I think the answer is B

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Hii please help me!!!!!

inysia [295]

It should be eight if I remember correctly

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2 years ago

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What is the number that has the same absolute value as 81

LenaWriter [7]

The absolute value of -81 has the same absolute value as that of 81 because they both have the same distance to 0.

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3 years ago

How do you solve 42 divided by 63

Dafna1 [17]

42 ÷ 63

63 -> 420

63x6=378

420-378=42

63->420

So, how many times does 63 go into 42? Well, it doesn't. So put down a zero on your paper, and then a decimal. So if we add a zero onto 42, it becomes 420. Well, 420 is divisible by 63. In fact, 63 goes into 420 6 times, making a total of 378. 420-378 = 42. Then the process begins again. So you've got a 0.6, and that six just keeps on repeating. On paper, you're gonna wanna put a dash over the six to show that it's repeating.

Anyways, the answer is .66 repeating.

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3 years ago

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Given sin theta= 6/11 and sec theta < 0, find cos theta and tan theta.

bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

$cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Substitute $sin(\theta)=\frac{6}{11}$ into the first equation, solve for the cosine and simplify. Then, you obtain:

$cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}$

As $sec\theta$ then $cos\theta$ :

$cos(\theta)=-\frac{\sqrt{85}}{11}$

Now we can find $tan\theta$ :

$tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}$

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3 years ago

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The time it takes Natalie to replace x cell phone screens is given by the equation t =

Alexxx [7]

Answer: 25 hours

Step-by-step explanation:

$t=1+3x$

8 screens

or

$x = 8$

Replace;

$t=1+3(8)$

$t=1+24$

$t=25h$

6 0

3 years ago