Let's think of something that one can hold against a page and draw a circle. Some examples are: a cup, a D battery, a can of soda, the tube from the inside of a paper towel roll, a can of beans, etc.
Think of the can of beans. The part that touches the page (and that you trace around with your pencil) is called a face.What these items have in common is that the faces at the ends are circles (they may or may not be the same size).
The name for this 3-D figure is called a cylinder. Her block, therefore, is a cylinder.
Technically, if the ends were ovals we would still call it a cylinder and so to make sure you have the one with the circles at the ends you would say you have a "right circular cylinder" but for most cases people just say "cylinder" and assume the ends are circles. It really depends what level (elementary, middle school, hs, college) of math you are doing whether just cylinder suffices.
Answer and Step-by-step explanation:
The way you complete this is by taking each points x and y and applying the translation. In this case the translation is x-7 and y+1.
Q's x and y are 1 , 1
R's x and y are 1 , 5
T's x and y are 5 , 1
S's x and y are 5 , 5
Now what you do is use the translation on all of these values.
Q's x and y turns into -6 , 2 (subtracted 7 to the 1 and added 1 to the 1)
R's x and y turns into -6 , 6
T's x and y are -2 , 2
S's x and y are -2 , 6
You can then plot the points on the graph and connect the lines to complete the reflection.
Hope this helps ! !
<3
The answers are:
Diameter: 30m
Circumference: 94.24777960769379
Area: 706.8583470577 m<span>2
I hope this helps you. Good luck with your work!</span>
Answer:
The domain of the function should be:
'x greater than or equal to negative -5'.
Hence, option A is true.
Step-by-step explanation:
Given the expression
The domain of a function is the set of input or arguments for which the function is real and defined
We know that the value, inside the radicand, is the number found inside a radical symbol which must be greater than 0, otherwise, it would make the function undefined,
i.e.
x-5 ≥ 0
x ≥ 5
In other words, the domain of the function should be:
'x greater than or equal to negative -5'.
Therefore, the domain of the function:
x ≥ 5
Hence, option A is true.
