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miss Akunina [59]
3 years ago
11

Write a polynomial in standard form with zeros at -2 and 3 !!!!! PLZ HELP

Mathematics
2 answers:
just olya [345]3 years ago
5 0
The answer is X^2 - X - 6
lara31 [8.8K]3 years ago
3 0

If the zeros are -2 and 3, then the factored form would be

(x+2) and (x-3)  

-2+2 = 0 and 3-3 = 0

A polynomial is written as ax^2 + bx + c

Expand (x+2) (x-3) using FOIL: Multiply each tern in one set of parenthesis by each term in the other set and then simplify by combining like terms:

x*x + x*-3 + 2*x + 2*-3

x^2 -3x + 2x -6

Polynomial in standard form:

x^2 -x -6

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A line's y-intercept is -10, and its slope is 1. What is its equation in slope-intercept form?
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5 0
2 years ago
Simplify the complex fraction. 2 1/2 / 5/8
lbvjy [14]
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5 0
3 years ago
Read 2 more answers
The  area of triangle formed by points of intersection of parabola y=a(x+5)(x−1) with the coordinate axes is 12. Find a if it is
Pie

We know that the points at which the parabola intersects the x axis are

(-5,0) and (1,0)

So the extent between these two points would be the base of the triangle

lets find the length of the base using the distance formula

\sqrt{[(-5-1)^{2}+(0-0)^{2} ]}

the base b=6

We will get the height of the triangle when we put x=0 in the equation

y=a(0+5)(0-1)

y=-5a

so height = -5a (we take +5a since it is the height)

We know that the area of the triangle =

\frac{1}{2} × 6 × (5a) = 12

15a=12

a= \frac{4}{5}


7 0
3 years ago
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