Write a polynomial in standard form with zeros at -2 and 3 !!!!! PLZ HELP
2 answers:
The answer is X^2 - X - 6
If the zeros are -2 and 3, then the factored form would be
(x+2) and (x-3)
-2+2 = 0 and 3-3 = 0
A polynomial is written as ax^2 + bx + c
Expand (x+2) (x-3) using FOIL: Multiply each tern in one set of parenthesis by each term in the other set and then simplify by combining like terms:
x*x + x*-3 + 2*x + 2*-3
x^2 -3x + 2x -6
Polynomial in standard form:
x^2 -x -6
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Since the equation says "cos(x-2)", we know that the horizontal displacement is 2 units.
The equation would be y=-2x-3
1 + m/3 < 6
Take 1 off both sides:
m / 3 < 5
Times both sides by 3:
m < 15
Answer: C, 9 units
Step-by-step explanation:
(-4, -3) is new point
It would be 2x/3y assuming that’s meant to say 15y^2
