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zavuch27 [327]
3 years ago
6

Choices3/43/55/44/5​

Mathematics
2 answers:
klio [65]3 years ago
7 0

Answer:

4/5

Step-by-step explanation:

sine is opposite over hypotenuse,

so it's 40/50=4/5

gladu [14]3 years ago
6 0
4/5
Hope this helps
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Which combination of shapes can be used to create the 3-D figure?
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An octagon has 8 sides and the shapes on the bottom of the shape are 8 rectangles.

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When constructing a perpendicular line through a point on a line, how can you verify that the lines constructed are perpendicula
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C

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HELP ASAP!! What is the average rate of change between x = -3 and x = 4 for the equation y = 8x2?
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Answer:

x=-3\\y=8(-3)^2\\y=8(9)\\y=72

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Step-by-step explanation:

Plz let me know if im right

3 0
2 years ago
Eva Maria borrowed money from her father and agreed to pay him 4% simple annual interest. At the end of 7 years, Eva Maria owes
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The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea
a_sh-v [17]
Check the picture below.

so the rhombus has the diagonals of AC and BD, now keeping in mind that the diagonals bisect each, namely they cut each other in two equal halves, let's find the length of each.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad 
C(\stackrel{x_2}{6}~,~\stackrel{y_2}{8})\qquad \qquad 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{[6-(-4)]^2+[8-(-2)]^2}\implies AC=\sqrt{(6+4)^2+(8+2)^2}
\\\\\\
AC=\sqrt{10^2+10^2}\implies AC=\sqrt{10^2(2)}\implies \boxed{AC=10\sqrt{2}}\\\\
-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
B(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad 
D(\stackrel{x_2}{4}~,~\stackrel{y_2}{0})\qquad \qquad BD=\sqrt{[4-(-2)]^2+[0-6]^2}
\\\\\\
BD=\sqrt{(4+2)^2+(-6)^2}\implies BD=\sqrt{6^2+6^2}
\\\\\\
BD=\sqrt{6^2(2)}\implies \boxed{BD=6\sqrt{2}}

that simply means that each triangle has a side that is half of 10√2 and another side that's half of 6√2.

namely, each triangle has a "base" of 3√2, and a "height" of 5√2, keeping in mind that all triangles are congruent, then their area is,

\bf \stackrel{\textit{area of the four congruent triangles}}{4\left[ \cfrac{1}{2}(3\sqrt{2})(5\sqrt{2}) \right]\implies 4\left[ \cfrac{1}{2}(15\cdot (\sqrt{2})^2) \right]}\implies 4\left[ \cfrac{1}{2}(15\cdot 2) \right]
\\\\\\
4[15]\implies 60

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3 years ago
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