Hello there!
1.) To start, first know that a cube has the same height, length, and width, meaning that all of the dimensions are 5-in. Then, when you slice it in half, this would mean that you have now reduced the width to half of its original. This would mean that the width is now 2.5 while the height and length remain 5.
Now that you have this information, you can now find the surface area by using this formula:
A= 2lw+2lh+2hw
Now plug in your values:
A=2(5)(2.5)+2(5)(5)+2(5)(2.5)
This would simplify to:
A=25+50+25
A=100 in squared
Therefore, the surface area of the two pieces are 100 inches squared.
2.) To start, first plug the measurements of the tank into the cylinder volume formula:
V=
r^2h
V=(2.75)^2(10)
V= 237.58 cubic feet
Now, we must find how long it will take the tank to empty if the rate is 3.7 cubic feet per minute so divide the volume (in feet) by the rate:
237.58/3.7= 64.2108...
Rounded to the nearest hundredth, it would take approximately 64.21 minutes to empty the take when it is full.
:)
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There will be 1.078x students next year and equation is number of students in next year = x + 7.8% of x
<h3><u>Solution:</u></h3>
Given, There are "x" number of students at helms.
The number of students increases by 7.8% each year which means if there "x" number of students in present year, then the number of students in next year will be x + 7.8% of x
Number of students in next year = number of students in present year + increased number of students.
Thus there will be 1.078x students in next year
I'm gonna say A. It makes the most sense to me.
Answer:
a)
a1 = log(1) = 0 (2⁰ = 1)
a2 = log(2) = 1 (2¹ = 2)
a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849
a4 = log(4) = 2 (2² = 4)
a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322
a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)
a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807
a8 = log(8) = 3 (2³ = 8)
a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )
a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322
b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:
log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that
a1 = 1
a2 = 2
a3 = 3
a4 = 4
a5 = 5
a6 = 6
a7 = 7
a8 = 8
a9 = 9
a10 = 10
I hope this works for you!!
