Answer:
f(x)=x^2
Step-by-step explanation:
if you wanted have a function where both of the robot's arms are in the air the function could be x to the power of any even number such f(x)=x^2, f(x)=x^4, f(x)=x^6, or even f(x)=x^10. And you could still do the same transformations with these equations.
2-5 x 1/2 = 0.2 (Length x Width)
The answer is B.
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take out some of the x's and take out a two so it should look like this.
2x^5(x2-2x-35)
2x5(x-7)(x+5)
x=0,7,-5
