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user100 [1]
3 years ago
12

Hey! PLEASE HELP!!!

Computers and Technology
1 answer:
Solnce55 [7]3 years ago
4 0

Answer:

change your computer date/skip the videos

Explanation:

hi there!  i've been using brainly for free for some time and found that there a few ways to bypass some of their free member restrictions.

first off, there's really not an easy way to skip the video, unless you want to get technical.  however, i've found that you can drag on the grey video bar on the bottom of the ad to skip to the very end, thus getting you the answer you need very quickly!

also, brainly has a 7 day answer restriction in place, which you can easily bypass by changing the date on your computer!  an easy way to do that is to hit the Windows key and type "date", after which a setting will pop up that reads "Date & time settings".  click on that or hit enter. then, tick off the slider that says "Set time automatically", and go down to "Set the date and time manually", after which you'll hit "Change" and change the day to a couple days in the future.  give it a second, refresh the brainly tab or re-search up your answer, and you should get a lot more daily answers!  one thing i must say about this method is that your computer's date will no longer be accurate. to fix this, you'll have to re-tick the slider that reads "Set time automatically", and it should fix your clock.

one more thing is that, instead of sending your parent an email, you can try to send yourself that email! unless it's an advertisement for buying brainly premium, there also should be no reason to even send the email in the first place, so try to bypass that when you can.

i hope this helps you!

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Write a C# program named ProjectedRaises that includes a named constant representing next year’s anticipated 4 percent raise for
nydimaria [60]

Answer:

using System;

class ProjectedRaises {

 static void Main() {

     const float raise = 0.04f;

     double salary1 = 0.0f,salary2 = 0.0f,salary3 = 0.0f;

Console.WriteLine("Current salary for each employee: ");

     salary1 = Single.Parse(Console.ReadLine());

     salary2 = Single.Parse(Console.ReadLine());

     salary3 = Single.Parse(Console.ReadLine());

     salary1 = salary1 + raise * salary1;

     salary2 = salary2 + raise * salary2;

     salary3 = salary3 + raise * salary3;

     Console.WriteLine("Next year salary for the employees are: ");

     Console.WriteLine(Math.Round(salary1));

     Console.WriteLine(Math.Round(salary2));

     Console.WriteLine(Math.Round(salary3));

}

}

Explanation:

This declares and initializes variable raise as a float constant

     const float raise = 0.04f;

This declares the salary of each employee as double

     double salary1 = 0.0f,salary2 = 0.0f,salary3 = 0.0f;

This prompts the user for the salaries of the employee

Console.WriteLine("Current salary for each employee: ");

The next three lines get the salary of the employees

<em>      salary1 = Single.Parse(Console.ReadLine());</em>

<em>      salary2 = Single.Parse(Console.ReadLine()); </em>

<em>      salary3 = Single.Parse(Console.ReadLine()); </em>

The next three lines calculate the new salaries of the employees

<em>      salary1 = salary1 + raise * salary1;</em>

<em>      salary2 = salary2 + raise * salary2;</em>

<em>      salary3 = salary3 + raise * salary3;</em>

This prints the header

     Console.WriteLine("Next year salary for the employees are: ");

The next three lines print the new salaries of the employees

     Console.WriteLine(Math.Round(salary1));

     Console.WriteLine(Math.Round(salary2));

     Console.WriteLine(Math.Round(salary3));

7 0
3 years ago
The mathematical constant Pi is an irrational number with value approximately 3.1415928... The precise value of this constant ca
tatiyna

Answer:

I am writing a Python program:

def approxPIsquared(error):

   previous = 8

   new_sum =0

   num = 3

   while (True):

       new_sum = (previous + (8 / (num ** 2)))

       if (new_sum - previous <= error):

           return new_sum

       previous = new_sum

       num+=2    

print(approxPIsquared(0.0001))

Explanation:

I will explain the above function line by line.

def approxPIsquared(error):  

This is the function definition of approxPlsSquared() method that takes error as its parameter and approximates constant Pi to within error.

previous = 8     new_sum =0      num = 3

These are variables. According to this formula:

Pi^2 = 8+8/3^2+8/5^2+8/7^2+8/9^2+...

Value of previous is set to 8 as the first value in the above formula is 8. previous holds the value of the previous sum when the sum is taken term by term. Value of new_sum is initialized to 0 because this variable holds the new value of the sum term by term. num is set to 3 to set the number in the denominator. If you see the 2nd term in above formula 8/3^2, here num = 3. At every iteration this value is incremented by 2 to add 2 to the denominator number just as the above formula has 5, 7 and 9 in denominator.

while (True):  This while loop keeps repeating itself and calculates the sum of the series term by term, until the difference between the value of new_sum and the previous is less than error. (error value is specified as input).

new_sum = (previous + (8 / (num ** 2)))  This statement represents the above given formula. The result of the sum is stored in new_sum at every iteration. Here ** represents num to the power 2 or you can say square of value of num.

if (new_sum - previous <= error):  This if condition checks if the difference between the new and previous sum is less than error. If this condition evaluates to true then the value of new_sum is returned. Otherwise continue computing the, sum term by term.

return new_sum  returns the value of new_sum when above IF condition evaluates to true

previous = new_sum  This statement sets the computed value of new_sum to the previous.

For example if the value of error is 0.0001 and  previous= 8 and new_sum contains the sum of a new term i.e. the sum of 8+8/3^2 = 8.88888... Then IF condition checks if the

new_sum-previous <= error

8.888888 - 8 = 0.8888888

This statement does not evaluate to true because 0.8888888... is not less than or equal to 0.0001

So return new_sum statement will not execute.

previous = new_sum statement executes and now value of precious becomes 8.888888...

Next   num+=2  statement executes which adds 2 to the value of num. The value of num was 3 and now it becomes 3+2 = 5.

After this while loop execute again computing the sum of next term using       new_sum = (previous + (8 / (num ** 2)))  

new_sum = 8.888888.. + (8/(5**2)))

This process goes on until the difference between the new_sum and the previous is less than error.

screenshot of the program and its output is attached.

6 0
3 years ago
I need help thanks please!
maw [93]

Answer:

a) to persuade

she is doing this to propose an idea to the boss of the company

6 0
3 years ago
Read 2 more answers
Cindy tried to delete a customer but the customer still had open invoices so the system would not allow her to delete the custom
Verdich [7]

Answer:

The answer is "Referential integrity".

Explanation:

This relates to one aspect of data integrity. Data across multiple tables are linked via relationships. In view of the distinct customer & invoice tables, each invoice table should have the primary key specified throughout the Customer table, for instance. Whenever the invoice table contains a customer ID reference. This ID including its customer will be only a table of the customer.

8 0
3 years ago
To find out how much ram is installed on a machine, in windows go to the user: a power ______ is a part inside a computer case t
shusha [124]
<span>a power _supply_ is a part inside a computer case that supplies power to the motherboard and other devices that are installed user: when a hard drive is first recognized by windows, it is assigned the _basic_ disk status user: utilize a _64_-bit os if you are looking for increased performance and you have a system that can support it.</span>
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