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3 years ago

Please help me with the first half

Mathematics

1 answer:

Triss [41]3 years ago

7 0

Answer:

a) 12:45 am

b) 7:30 pm

c) 20:15

d) 0:00

Step-by-step explanation:

a) We know that the 24-hour clock has no "am" or "pm" because in a day, there are 24 hours, so "pm" would simply be more than 12 hours.

The 12th hour marks noon, which is "12:00 pm" in 12-hour times. Anything after that would start from 1 and would be marked with a pm.

So 12:45 in 12-hour format would be 12:45 pm because it's passed the noon-mark, which is the 12th hour. Anything after noon would be marked with a "pm."

b) Same thing here: 19:30 has also passed the noon mark, the 12th hour. It would be marked with a "pm."

But there is no "19 'o clock" in 12-hour format (hence the 12-hour 12 hours). So to find that, we know that it has already passed noon. We can subtract to find how many hours it has passed noon:

19 - 12 = 7

So it's the 7th hour.

So it would be 7:30 pm.

c) Because there is no "am" or "pm" in the 24-hour clock, we have to see how many hours past noon it has been.

8:15 pm means it has passed noon by 8 hours and 15 minutes. So we add this to the noon mark (first 12 hours of the day).

12 + 8 = 20

This is our hours. We can attach it to the minutes: 20:15.

d) Midnight in 12-hour terms would be 12:00 am. It would be officially the next day, and it's a reset button.

If it were Saturday today, and it's 11:59 pm, it's still Saturday. But once that clock turns 12:00 pm, it's Sunday.

This means that no time has passed during Sunday yet—it just reset.

So it would be 0:00 because no time has passed officially on Sunday yet.

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2. Assume f(x) = g(x). Which of the following functions may be used to represent the equation 3x+2 = 7x + 6? A. f(x) = x + 2, g(

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Answer:

C. f(x) = 3·x + 2, g(x) = 7·x + 6

Step-by-step explanation:

The given equations relates to the property of equality of values;

The given formula for the association between f(x) and g(x) is f(x) = g(x)

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3 years ago

A snowboard is on sale for $476. If the

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Answer:

15%

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we call the original price 100% and to find the discount amount :

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3 years ago

NEED HELP ASAP!!

Solnce55 [7]

Answer:

Only Cory is correct

Step-by-step explanation:

The gravitational pull of the Earth on a person or object is given by Newton's law of gravitation as follows;

$F =G\times \dfrac{M \cdot m}{r^{2}}$

Where;

G = The universal gravitational constant

M = The mass of one object

m = The mass of the other object

r = The distance between the centers of the two objects

For the gravitational pull of the Earth on a person, when the person is standing on the Earth's surface, r = R = The radius of the Earth ≈ 6,371 km

Therefore, for an astronaut in the international Space Station, r = 6,800 km

The ratio of the gravitational pull on the surface of the Earth, F₁, and the gravitational pull on an astronaut at the international space station, F₂, is therefore given as follows;

$\dfrac{F_1}{F_2} = \dfrac{ \dfrac{M \cdot m}{R^{2}}}{\dfrac{M \cdot m}{r^{2}}} = \dfrac{r^2}{R^2} = \dfrac{(6,800 \ km)^2}{(6,371 \ km)^2} \approx 1.14$

∴ F₁ ≈ 1.14 × F₂

F₂ ≈ 0.8778 × F₁

Therefore, the gravitational pull on the astronaut by virtue of the distance from the center of the Earth, F₂ is approximately 88% of the gravitational pull on a person of similar mass on Earth

However, the International Space Station is moving in its orbit around the Earth at an orbiting speed enough to prevent the Space Station from falling to the Earth such that the Space Station falls around the Earth because of the curved shape of the gravitational attraction, such that the astronaut are constantly falling (similar to falling from height) and appear not to experience gravity

Therefore, Cory is correct, the astronauts in the International Space Station, 6,800 km from the Earth's center, are not too far to experience gravity.

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