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Keith_Richards [23]
3 years ago
12

Please help me with the first half

Mathematics
1 answer:
Triss [41]3 years ago
7 0

Answer:

a) 12:45 am

b) 7:30 pm

c) 20:15

d) 0:00

Step-by-step explanation:

a) We know that the 24-hour clock has no "am" or "pm" because in a day, there are 24 hours, so "pm" would simply be more than 12 hours.

The 12th hour marks noon, which is "12:00 pm" in 12-hour times. Anything after that would start from 1 and would be marked with a pm.

So 12:45 in 12-hour format would be 12:45 pm because it's passed the noon-mark, which is the 12th hour. Anything after noon would be marked with a "pm."

b) Same thing here: 19:30 has also passed the noon mark, the 12th hour. It would be marked with a "pm."

But there is no "19 'o clock" in 12-hour format (hence the 12-hour 12 hours). So to find that, we know that it has already passed noon. We can subtract to find how many hours it has passed noon:

19 - 12 = 7

So it's the 7th hour.

So it would be 7:30 pm.

c) Because there is no "am" or "pm" in the 24-hour clock, we have to see how many hours past noon it has been.

8:15 pm means it has passed noon by 8 hours and 15 minutes. So we add this to the noon mark (first 12 hours of the day).

12 + 8 = 20

This is our hours. We can attach it to the minutes: 20:15.

d) Midnight in 12-hour terms would be 12:00 am. It would be officially the next day, and it's a reset button.

If it were Saturday today, and it's 11:59 pm, it's still Saturday. But once that clock turns 12:00 pm, it's Sunday.

This means that no time has passed during Sunday yet—it just reset.

So it would be 0:00 because no time has passed officially on Sunday yet.

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That person shakes hands with 29 other classmates.

Take another person different from the first, we'll call him the 'second'. Since he has already shaken hands with the first, he shakes hands with 28 other classmates.

The 'third' person will likewise shake hands with 27 other classmates, and so on.

Hence, the total number of handshakes is 29+28+27+...+2+1 = 29*30/2=435 handshakes
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The best answer to the question that is being presented above would be true. It is deemed true that graphing recorded data from a chart or table would be helpful for interpreting trends or patterns. This is because the graph shows the distribution of data and has an overall picture on how the data moves.
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2. Assume f(x) = g(x). Which of the following functions may be used to represent the equation 3x+2 = 7x + 6? A. f(x) = x + 2, g(
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Answer:

C. f(x) = 3·x + 2, g(x) = 7·x + 6

Step-by-step explanation:

The given equations relates to the property of equality of values;

The given formula for the association between f(x) and g(x) is f(x) = g(x)

The given equation of two expressions is 3·x + 2 = 7·x + 6

By transitive property of equality, the two above equations are correct when f(x) = 3·x + 2 and g(x) = 7·x + 6

Therefore, the function that may be used to represent the equation is option C; f(x) = 3·x + 2, g(x) = 7·x + 6.

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A snowboard is on sale for $476. If the
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Answer:

15%

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we call the original price 100% and to find the discount amount :

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3 years ago
NEED HELP ASAP!!
Solnce55 [7]

Answer:

Only Cory is correct

Step-by-step explanation:

The gravitational pull of the Earth on a person or object is given by Newton's law of gravitation as follows;

F =G\times \dfrac{M \cdot m}{r^{2}}

Where;

G = The universal gravitational constant

M = The mass of one object

m = The mass of the other object

r = The distance between the centers of the two objects

For the gravitational pull of the Earth on a person, when the person is standing on the Earth's surface, r = R = The radius of the Earth ≈ 6,371 km

Therefore, for an astronaut in the international Space Station, r = 6,800 km

The ratio of the gravitational pull on the surface of the Earth, F₁, and the gravitational pull on an astronaut at the international space station, F₂, is therefore given as follows;

\dfrac{F_1}{F_2} = \dfrac{ \dfrac{M \cdot m}{R^{2}}}{\dfrac{M \cdot m}{r^{2}}} = \dfrac{r^2}{R^2}  = \dfrac{(6,800 \ km)^2}{(6,371 \ km)^2} \approx  1.14

∴ F₁ ≈ 1.14 × F₂

F₂ ≈ 0.8778 × F₁

Therefore, the gravitational pull on the astronaut by virtue of the distance from the center of the Earth, F₂ is approximately 88% of the gravitational pull on a person of similar mass on Earth

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Therefore, Cory is correct, the astronauts in the International Space Station, 6,800 km from the Earth's center, are not too far to experience gravity.

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