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8_murik_8 [283]
3 years ago
9

Use the distributive property to write an equivalent expression for 12+18. PLS HELP

Mathematics
1 answer:
shepuryov [24]3 years ago
6 0

Answer:

6(2+3)

Step-by-step explanation:

6x2=12

6x3=18

12+18

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A merchant selling sunglasses can place 8 large boxes or 10 small boxes into a carton for shipping. In one shipment he sent a to
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<h2>Answer:</h2>

64 large boxes and 60 small boxes.

<h2>Step-by-step explanation:</h2>

Here we must use the concept of multiples. A multiple of a number result of the multiplication of that number by an integer. For instance, 2, 4, 6, 8 are multiples of 2. The following chart shows our statement:

\begin{array}{cccccccccc}Number\,of\,boxes & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9\\Large & 8 & 16 & 24 & 32 & 40 & 48 & 56 & 64 & 72\\Small & 10 & 20 & 30 & 40 & 50 & 60 & 70 & 80 & 90\end{array}

So we need to choose the number of small and large boxes such that the sum is 124 boxes of sunglasses and the number of large boxes is greater than the number of small boxes. From the table, the correct solution is:

64 large boxes and 60 small boxes because 64 + 60 = 124 and 64 > 60

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A new 2006 Honda head was values at $25000. It depresides at a rate of 13% a year.
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Answer:

1. It's value in 2009 was $16,462.575

2. It's value in 2020 will be $3,558.

Step-by-step explanation:

The equation for the value of car after t years has the following format.

V(t) = V(0)(1-r)^{t}

In which V(t) is the value after t years, V(0) is the initial value and r is the ratio of depreciation.

In this problem, we have that:

V(0) = 25000, r = 0.13

So

V(t) = V(0)(1-r)^{t}

V(t) = 25000(1-0.13)^{t}

V(t) = 25000(0.87)^{t}

1. What was its value in 2009

2009 is 3 years after 2006, so this is V(3)

V(t) = 25000(0.87)^{t}

V(3) = 25000(0.87)^{3}

V(3) = 16462.575

It's value in 2009 was $16,462.575

2.What will be its value in 2020?

2020 is 14 years after 2006, so this is V14)

V(t) = 25000(0.87)^{t}

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V(14) = 3558

It's value in 2020 will be $3,558.

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