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3 years ago

6

Adjust the window so you can find all of the points of intersection for the system of equations. What are the roots of the origi

nal polynomial equation? Check all that apply. –6 0 6 –4 3 8

2 answers:

atroni [7]3 years ago

6 0

Answer:

Your answer would be 6, -4, and 3

Step-by-step explanation:

goldfiish [28.3K]3 years ago

3 0

Answer:

C, D, E

Step-by-step explanation:

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Evaluate the expression when a=14 and b=6. 5b/32a2

leonid [27]

Answer:

28/16071 as a decimal 0.00174226...

Step-by-step explanation:

Hope this helps!

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3 years ago

Find the absolute value and the opposite of the integer. –98

Lena [83]

<span>Absolute value of -98 is 98

Hope I helped:D </span>

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3 years ago

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Select the non-linear function from the list of the following:

solong [7]

Answer:

c

Step by step explanation: Linear equations don't have exponents, so that makes option c nonlinear

6 0

2 years ago

Solve for k please help!!!

grin007 [14]

Answer: k = 59°

Steps:
180 - 77 = 103

103 + 18 + k = 180
121 + k = 180
k = 180 - 121
k = 59

Check:
103 + 18 + k = 180
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3 years ago

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A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

3 years ago