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pantera1 [17]
3 years ago
12

How would the flow of energy in a forest ecosystem change if the deer population went extinct? A. Other members of the food chai

n could also become endangered. B. There would be less energy because there would be fewer plants. C. The population of animals higher up on the food chain would increase. D. This would have no impact on organisms in the ecosystem. Pls help me
Advanced Placement (AP)
2 answers:
nikdorinn [45]3 years ago
8 0

Answer:

a

Explanation:

if you take one organism out of the ecosystem it would have a huge affect on animals that eat it and plats that it eats. A lot of the animals that eat the dear would have a decrease in population because they don't have the deer to eat then the animals that eat the animals that eat the deer would also decrease because the animals that eat the deers population decrease.

FinnZ [79.3K]3 years ago
5 0

Answer: A. Other members of the food chain could also become endangered.

Explanation:

If the deer go extinct, it could make the the carnivores go endangered, because the carnivores eat the deer, and without the deer, the carnivores would get endangered.

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2 years ago
Surface Area of a can is 517.8 cm^2. Maximize the volume of this can using the measured surface area.
mafiozo [28]

Answer:

r = 5.24 --- Radius

h = 10.48 --- Height

Explanation:

Given

Object: Can (Cylinder)

Surface\ Area = 517.8cm^2

Required

Maximize the volume

The surface area is:

S.A = 2\pi r^2 + 2\pi rh

Substitute 517.8 for S.A

517.8 = 2\pi r^2 + 2\pi rh

Divide through by 2

258.9 = \pi r^2 + \pi rh

Factorize:

258.9 = \pi r(r + h)

Divide through by \pi r

\frac{258.9}{\pi r} = r + h

Make h the subject

h = \frac{258.9}{\pi r} - r --- (1)

Volume (V) is calculated as:

V = \pi r^2h

Substitute (1) for h

V = \pi r^2(\frac{258.9}{\pi r} - r)

Open Bracket

V = 258.9r - \pi r^3

Differentiate V

V' = 258.9 - 3\pi r^2

Set V' to 0

0 = 258.9 - 3\pi r^2

Collect Like Terms

3\pi r^2 = 258.9

Divide through by 3

\pi r^2 = 86.3

Divide through by \pi

r^2 = \frac{86.3}{\pi}

r^2 = \frac{86.3*7}{22}

r^2 = \frac{604.1}{22}

Take square root of both sides

r = \sqrt{\frac{604.1}{22}

r = 5.24

Recall that:

h = \frac{258.9}{\pi r} - r

Substitute 5.24 for r

h = \frac{258.9}{\pi * 5.24} - 5.24

h = \frac{258.9*7}{22 * 5.24} - 5.24

h = \frac{1812.3}{115.28} - 5.24

h = 15.72 - 5.24

h = 10.48

Hence, the dimension that maximize the volume is:

r = 5.24 --- Radius

h = 10.48 --- Height

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3 years ago
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yuradex [85]
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Answer:

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Explanation:

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