2 years ago

C^2cos^2 B+ b^2cos^2 C + bc cos (B - C) = 1/2(a^2+b^2+ c^2)

Mathematics

1 answer:

melisa1 [442]2 years ago

5 0

Answer:

me vale

Step-by-step explanation:

spanish hgjddjzfurdoydoydotroyd6odo6eoyeoydtodyodo6do55od5od5odo5dtodtofpydypff6

You might be interested in

How do i solve this?

timofeeve [1]

(f - g)(x) = f(x) - g(x)

… = (3x² - 4) - (4x + 1)

… = 3x² - 4x - 5

3 0

2 years ago

What is the 75th term of the arithmetic sequence -1, 5, 11

lana [24]

Answer:

75th term = 443

Step-by-step explanation:

$a_{n}=a_{1}+d(n-1) \\a_{n}=-1+6(n-1) \\a_{75}=-1+6(75-1) \\a_{75}=-1+6(74)\\a_{75}=-1+444\\a_{75}=443 \\\\$

7 0

3 years ago

Wendy kept track of the number of text messages she sent each day for three weeks. Drag and drop each number into the boxes to c

NeX [460]

Answer:

0-9 = 4

10-19 = 3

20-29 = 9

30-39 = 5

Step-by-step explanation:

8 0

2 years ago

Please help thank you

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

3 0

2 years ago

How do you multiply fractions by whole numbers?

umka21 [38]

Rewrite the whole number as a fraction. To rewrite a whole number as a fraction, simply place the whole number over 1. ...Multiply the numerators of the two fractions. ...Multiply the denominators of the two fractions. ...Simplify.

4 0

2 years ago

Read 2 more answers

C^2cos^2 B+ b^2cos^2 C + bc cos (B - C) = 1/2(a^2+b^2+ c^2)​

C^2cos^2 B+ b^2cos^2 C + bc cos (B - C) = 1/2(a^2+b^2+ c^2)