2 years ago

C^2cos^2 B+ b^2cos^2 C + bc cos (B - C) = 1/2(a^2+b^2+ c^2)

Mathematics

1 answer:

melisa1 [442]2 years ago

5 0

Answer:

me vale

Step-by-step explanation:

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Answers to page 691-693 #1-30

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C^2cos^2 B+ b^2cos^2 C + bc cos (B - C) = 1/2(a^2+b^2+ c^2)​

C^2cos^2 B+ b^2cos^2 C + bc cos (B - C) = 1/2(a^2+b^2+ c^2)