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Arte-miy333 [17]
3 years ago
6

Cooper is taking a multiple choice test with a total of 80 points available. Each question is worth exactly 4 points. What would

be Cooper's test score (out of 80) if he got 2 questions wrong? What would be his score if he got xx questions wrong?
Mathematics
1 answer:
VLD [36.1K]3 years ago
3 0

Answer:

80-4(2)=72; 80-4(x) if he got x wrong.

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Answer:

Step-by-step explanation:

2a^-a-13=2

Subtract 2 from both sides :

2a^2-a-13=2=2-2

2a^2-a-15=0

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(2a+5) (a-3)=0

Set factors equal to 0 :

2a+5=0 or  a-3=0

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A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2-cm and a standard dev
Varvara68 [4.7K]

Answer:

The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.

Step-by-step explanation:

We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.

Let \bar X = <u><em>the average length of rods in a randomly selected bundle of steel rods</em></u>

The z-score probability distribution for the sample mean is given by;

                            Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean length of rods = 259.2 cm

           \sigma = standard deviaton = 2.1 cm

           n = sample of steel rods = 17

Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P(\bar X > 259 cm)

 

     P(\bar X > 259 cm) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{259-259.2}{\frac{2.1}{\sqrt{17} } } ) = P(Z > -0.39) = P(Z < 0.39)

                                                                = <u>0.65173</u>

The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.

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