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Oksi-84 [34.3K]
2 years ago
14

Q2 - Using fractions

Mathematics
1 answer:
Degger [83]2 years ago
7 0

Total Earned Saturday: $45

Total Earned Sunday: $63

Total: $108

Time and a quarter means that you divide his normal rate by 4 and add that to his normal rate.

9/4 = 2.25     2.25 + 9 = 11.25

Jarvis makes $11.25 an hour on Saturdays.

Since he worked 4 hours, you multiply,

11.25 x 4 = 45.

<h3>What is the normal rate?</h3>

Time and three quarters mean that you multiply his normal rate by 3/4 and add that to his normal rate

9x0.75 = 6.75     6.75 + 9 = 15.75

Jarvis makes $15.75 an hour on Sundays. Since he worked 4 hours, you multiply 15.75 x 4 = 63.

To get the total, you add his earnings on Saturday and earnings on Sunday

45 + 63 = 108.

To learn more about the using fractions visit:

brainly.com/question/78672

#SPJ1

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150 - x - 2x = 120 + 2x
Svetach [21]

Answer:

x = 6

Step-by-step explanation:

Step 1: Write equation

150 - x - 2x = 120 + 2x

Step 2: Solve for <em>x</em>

  1. Combine like terms: 150 - 3x = 120 + 2x
  2. Add 3x to both sides: 150 = 120 + 5x
  3. Subtract 120 on both sides: 30 = 5x
  4. Divide both sides by 5: 6 = x
  5. Rewrite: x = 6

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

150 - 6 - 2(6) = 120 + 2(6)

144 - 12 = 120 + 12

132 = 132

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The line integral of xydx×x^2y^3dy where c is the triangle with points (0,0) (1,0) (1,2) using green's theorem
lyudmila [28]
If \mathcal C is the boundary of the triangle D, then by Green's theorem

\displaystyle\int_{\mathcal C}xy\,\mathrm dx+x^2y^3\,\mathrm dy=\iint_D\left(\frac{\partial(x^2y^3)}{\partial x}-\frac{\partial(xy)}{\partial y}\right)\,\mathrm dA
=\displaystyle\int_{x=0}^{x=1}\int_{y=0}^{y=2x}(2xy^3-x)\,\mathrm dy\,\mathrm dx
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The diagram shows a rectangle 15cm long and 13cm wide.It has been split into four smaller rectangles. write the area of each sma
shusha [124]
<h2>Answer:</h2><h3>The Answer is in the explanation</h3><h2>Step-by-step explanation:</h2>

<h3><em>length of the rectangle</em> = 15 cm</h3><h3><em>Breadth of the rectangle = 13 cm</em></h3><h3 /><h3><em>Area of the rectangle = length × breadth</em></h3><h3><em>Area of the rectangle = length × breadth = 15cm × 13cm =</em></h3>

<em>195 cm^{2}</em>

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<em>\frac{195cm{}^{2} }{4}</em>

<h3><em>=</em></h3>

<em>48.75 {cm}^{2}</em>

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2. Two angles have a common vertex but no common side. How can you tell whether the angles are vertical angles?
Maksim231197 [3]

Explanation:

The angles are <em>vertical angles</em> if the opposites of the rays forming one of the angles are the rays forming the other angle.

More formally, if V is the common vertex, and ...

  • R is a point on one of the rays forming Angle 1
  • S is a point on the ray that is the opposite of ray VR
  • T is a point on the other ray forming Angle 1
  • U is a point on the ray that is the opposite of ray VT

Then angle RVT and angle SVU are vertical angles.

___

Another way to say this is that points R, V, S are collinear, as are points T, V, U, and the two angles of interest are RVT and SVU.

If the above conditions cannot be met, then the angles are not vertical angles.

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