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2 years ago

Suppose a system of two linear equations has one solution. What must be true about the graphs of the two equations?

Mathematics

2 answers:

Reika [66]2 years ago

6 0

Answer:

They have to intersect at one point

Step-by-step explanation:

vivado [14]2 years ago

4 0

Answer:

They intersect at one point

Step-by-step explanation:

I took the test and got 100%

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The Candela brothers own two pizza restaurants, one on Park Street and one on Bridge Road.

koban [17]

The mean, median and mode are measures of central tendency, that is they tend to indicate the location middle of the data

Required values;

(a) The performance for the week for Park Street

Revenue is Q₂ < $7,500 < Q₃

The sales for the week is better than 72.91% of all sales

The performance for the week for Bridge Road

Revenue; Q₂ < $7,100 < Q₃

The sale for the week is better than 59.87% of all sales

(b) The mean is $3611

The median is $3,600

The standard deviation is $3250

The Interquartile range is $6075

Reason:

The table of values that maybe used to find a solution to the question is given as follows;

$\begin{array}{|l|l|l|}\mathbf{Variable} &\mathbf{Park}&\mathbf{Bridge}\\N&36&40\\Mean&6611&5989\\SE \ Mean&597&299\\StDev&3580&1794\\Minimum&800&1800\\Q_1&3600&5225\\Median&6600&6000\\Q_3&9675&7625\\Maximum&14100&8600\end{array}\right]$

(a) Park Street revenue = $7,500

Bridge Road's revenue = $7,100

The two stores sold close to but below the 75th percentile

Bridge Road revenue;

The z-score is given as follows;

$Z = \dfrac{x - \mu }{\sigma }$

$Z = \dfrac{7100 - 5,989 }{1794 } \approx 0.6193$

From the Z-Table, we have;

The percentile= 0.7291

Therefore, the sale for the week for Park Street is better than 72.91% of all the sales

Park Street revenue;

The z-score is given as follows;

$Z = \dfrac{7500 - 6611}{3580} \approx 0.25$

From the Z-Table, we have;

The percentile = 0.5987

Therefore, the sale for the week is better than 59.87 % of all the sales

(b) Given that the operating cost is $3,000, frim which we have;

The subtracted value is subtracted from the mean and median to find the new value

Profit = The revenue - Cost

New mean = 6611 - 3000 = 3611

The new mean = $3,611

The new median = 6600 - 3000 = 3600

The new median = $3,600

The standard deviation and the interquartile range remain the same, therefore, we have;

The standard deviation = $3,580

The interquartile range = 9675 - 3600 = 6075

The interquartile range = 6075

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5 0

2 years ago

Question in image. :)

quester [9]

a. f(a) =5a+12

we have 1. a=6

Therefore, where ever we find a we'll substitute in 6

f(6) =5(6) +12

6f=30+12

6f=42

so therefore 1. a=6 will match c on the right

2. a=2

f(2) =5(2) +12

2f = 10+12

2f = 22

therefore 2. a=2 will match a on the right

3. a=4

f(4) =5(4) +12

4f=20+12

4f=32

therefore 3. a=4 will match d on the right

4. a=5

f(5) =5(5) +12

5f=25+12

5f=37

therefore 4. a=5 will match b on the right

7 0

3 years ago

Without using technology, describe the end behavior of f(x) = 3x32 + 8x2 − 22x + 43.

mr Goodwill [35]

F(x) = 3x^32 + 8x^2 -22x +43

The ends of all the polynomials with even degree behave like quadratic functions.

Given the the coefficient of x^32 is positive, the function opens upwards. Then the two ends go up.

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3 years ago

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How many combinations of a president, vice-president, secretary, and treasurer can be chosen from a group of 12 students?

VMariaS [17]

The answer is a 11,880

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3 years ago

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A semicircle has a center at X and diameter WZ. The radius XY of the semicircle has a length of 2. The chord YZ has a length of

siniylev [52]

, it is important to recognize that the point (x,y) in the first quadrant represents any point on the semicircle. In Figure 2, the same semicircle is shown with the inscribed rectangle drawn for three different values of x.

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3 years ago