Answer:
![12 \sqrt{2}](https://tex.z-dn.net/?f=12%20%5Csqrt%7B2%7D%20)
Step-by-step explanation:
Taking the terms one at a time,
![\frac{14}{ \sqrt{2} } \\ \frac{14 * \sqrt{2} }{ \sqrt{2} * \sqrt{2} } \\ \frac{14 \sqrt{2} }{2} \\ 7 \sqrt{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B14%7D%7B%20%5Csqrt%7B2%7D%20%7D%20%20%5C%5C%20%20%20%5Cfrac%7B14%20%2A%20%20%5Csqrt%7B2%7D%20%7D%7B%20%5Csqrt%7B2%7D%20%2A%20%20%5Csqrt%7B2%7D%20%20%7D%20%20%5C%5C%20%20%20%5Cfrac%7B14%20%20%5Csqrt%7B2%7D%20%7D%7B2%7D%20%20%5C%5C%20%207%20%5Csqrt%7B2%7D%20%20)
![\sqrt{50} \\ \sqrt{25 * 2} \\ \sqrt{25}* \sqrt{2} \\ 5 * \sqrt{2} \\ 5 \sqrt{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B50%7D%20%5C%5C%20%20%5Csqrt%7B25%20%2A%202%7D%20%5C%5C%20%20%5Csqrt%7B25%7D%2A%20%20%5Csqrt%7B2%7D%20%20%20%20%5C%5C%205%20%2A%20%20%5Csqrt%7B2%7D%20%20%20%5C%5C%205%20%5Csqrt%7B2%7D%20)
Adding the terms, you have;
![7 \sqrt{2} + 5 \sqrt{2} =(7 + 5) \sqrt{2} = 12 \sqrt{2}](https://tex.z-dn.net/?f=7%20%5Csqrt%7B2%7D%20%2B%205%20%5Csqrt%7B2%7D%20%3D%287%20%2B%205%29%20%5Csqrt%7B2%7D%20%3D%2012%20%5Csqrt%7B2%7D%20%20%20%20)
Hope it helps!
I'm out!
Answer:
3,000,000. 6 Zeros. 898,752,432,640
299,792 kilometers per second is the speed of light normally
Step-by-step explanation:
Answer:
We conclude that the two ordered pairs (0, 0) and (-2, 2) are the solutions of the equation y = 2x² + 3x.
Step-by-step explanation:
Given the expression
y = 2x² + 3x
Substituting x = 0
y = 2(0)² + 3(0)
y = 0+0
y = 0
Thus, the ordered pair is: (0, 0)
Now, substituting x = -2
y = 2x² + 3x
y = 2(-2)² + 3(-2)
y = 8 - 6
y = 2
Thus, the ordered pair is: (-2, 2)
Therefore, we conclude that the two ordered pairs (0, 0) and (-2, 2) are the solutions of the equation y = 2x² + 3x.
Sand to cement
7:3
210:x
ask yourself what number is needed to multiply by 7 to get 210 ( so you'd divide 210 by 7 which is 30). Multiply the other side by thirty as well to get the value of x
3*30 which is 90
I would say Song 1 on the top could be NO, and Song 1 on the bottom could be ON, then Song 2 on the very top could be NO again, then on the bottom of the very top could OO, then on the bottom of that could be NN, and on he very bottom could be ON.
Hope this helps.