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3 years ago

Solve the polynomial equation by factoring. 3x^4+11^3-4x^2=0

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

8 0

Answer:

Step-by-step explanation:

Sidana [21]3 years ago

5 0

Step-by-step explanation:

$3{x}^{4} + 11 {x}^{3} - 4 {x}^{2} = 0 \\ factor \: {x}^{2} out \: of \: 3 {x}^{4} + 11 {x}^{3} - 4 {x}^{2} \\ \\ {x}^{2} ( 3{x}^{2} + 11x - 4) = 0 \\ {x}^{2} (3x - 1)(x + 4) = 0 \\ {x}^{2} = 0 \\ 3x - 1 = 0 \\ x + 4 = 0 \\$

$x = 0 \\ x = \frac{1}{3} \\ x = - 4 \\$

The final solution is

x=(0 , 1/3 , -4 )

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3 years ago

How are exponents and radicals used to present roots of real numbers

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$\sqrt[n]{a} =a^{\frac{1}{n}}$

Explanation:

Roots of real numbers can be represented by radicals or by exponents.

First, I present some examples to show how exponents and radicals are related, and then generalize.

$\sqrt{4}=4^{(\frac{1}{2})}=(2^2)^\frac{1}{2}=(2)^{\frac{2}{2}}=2^1=2\\\\\\\sqrt{25}=(25)^{\frac{1}{2}}=(5^2)^{\frac{1}{2}}=(5)^{\frac{2}{2}}=5^1=5$

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When you write 5² = 25, then 5 is the square root of 25.

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