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yan [13]
3 years ago
8

Solve the polynomial equation by factoring. 3x^4+11^3-4x^2=0

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

0

Step-by-step explanation:

Sidana [21]3 years ago
5 0

Step-by-step explanation:

3{x}^{4}  + 11 {x}^{3}  - 4 {x}^{2}  = 0 \\ factor \:  {x}^{2} out \: of \: 3 {x}^{4} + 11 {x}^{3}   - 4 {x}^{2}  \\  \\  {x}^{2} ( 3{x}^{2}  + 11x - 4) = 0 \\  {x}^{2} (3x - 1)(x + 4) = 0 \\  {x}^{2}  = 0 \\ 3x - 1 = 0 \\ x + 4 = 0 \\

x = 0 \\ x =  \frac{1}{3}  \\ x =  - 4 \\

The final solution is

x=(0 , 1/3 , -4 )

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1) Determine the discriminant of the 2nd degree equation below:
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\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}

We have, Discriminant formula for finding roots:

\large{ \boxed{ \rm{x =  \frac{  - b \pm \:  \sqrt{ {b}^{2}  - 4ac} }{2a} }}}

Here,

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1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

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➝ D = 4 - (-12)

➝ D = 4 + 12

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2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5\pm  \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}

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\large{\boxed{ \rm{ \longrightarrow \: x =  - 2 \: or  - 3}}}

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\large{ \rm{ \longrightarrow \: x =  \dfrac{  - 2 \pm  \sqrt{ {2}^{2}  - 4 \times 1 \times 1} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 2 \pm 0}{2} }}

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\large{\boxed{ \rm{ \longrightarrow \: x =  - 1 \: or \:  - 1}}}

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\large{ \rm{ \longrightarrow \: x =  \dfrac{1 \pm 9}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \:  - 4}}}

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So here,

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