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yan [13]
3 years ago
8

Solve the polynomial equation by factoring. 3x^4+11^3-4x^2=0

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

0

Step-by-step explanation:

Sidana [21]3 years ago
5 0

Step-by-step explanation:

3{x}^{4}  + 11 {x}^{3}  - 4 {x}^{2}  = 0 \\ factor \:  {x}^{2} out \: of \: 3 {x}^{4} + 11 {x}^{3}   - 4 {x}^{2}  \\  \\  {x}^{2} ( 3{x}^{2}  + 11x - 4) = 0 \\  {x}^{2} (3x - 1)(x + 4) = 0 \\  {x}^{2}  = 0 \\ 3x - 1 = 0 \\ x + 4 = 0 \\

x = 0 \\ x =  \frac{1}{3}  \\ x =  - 4 \\

The final solution is

x=(0 , 1/3 , -4 )

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after taking nine test Carols average grade in her Italian classes 90 her teacher drops the lowest of the nine test scores to de
Ostrovityanka [42]

Answer:

82

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The sum of scores for the 9 tests must be 90 * 9 = 810. The sum of scores for the 8 tests is 8 * 91 = 728 so the lowest score is 810 - 728 = 82.

5 0
3 years ago
Please please please helpppp, (please show work if you can)
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Answer:

∴ m∠KIJ = 18°  and   m∠HIJ = 50°

Thus, option a is correct.

Step-by-step explanation:

From the figure, it is clear that:

m∠KIH = m∠HIJ + m∠KIJ

Given

  • m∠KIH = 68°
  • m∠KIJ = (2x + 6)°
  • m∠HIJ = (9x - 4)°

now substituting m∠KIH = 68°, m∠KIJ = (2x + 6)° and m∠HIJ = (9x - 4)° in the equation

m∠KIH = m∠HIJ + m∠KIJ

68° = (2x + 6)° + (9x - 4)°

switch sides

\left(2x+6\right)+\left(9x-4\right)=68

Group like terms

2x+9x+6-4=68

11x+2=68

Subtract 2 from both sides

11x+2-2=68-2

Simplify

11x=66

Divide both sides by 11

\frac{11x}{11}=\frac{66}{11}

Simplify

x=6

Hence, the value of x = 6

Therefore,

m∠KIJ = (2x + 6)° = 2(6) + 6 = 12 + 6 = 18°

m∠HIJ = (9x - 4)° = 9(6) - 4 = 54 - 4 = 50°

∴ m∠KIJ = 18°  and   m∠HIJ = 50°

Thus, option a is correct.

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