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Likurg_2 [28]
3 years ago
11

Given the exponential equation 3* = 243, what is the logarithmic form of the equation in base 10? (5 points)

Mathematics
1 answer:
Andrej [43]3 years ago
3 0

Answer:

x = \frac{log\ 243}{log\ 3}

Step-by-step explanation:

Given

3^x = 243

Required

Express as a logarithm

3^x = 243

Take log of both sides

log\ 3^x = log\ 243

Apply the following law of logarithm

log\ a^b = b\ log\ a

So, the expression becomes:

log\ 3^x = log\ 243

x\ log\ 3 = log\ 243

Divide both sides by log 3

\frac{x\ log\ 3}{log\ 3} = \frac{log\ 243}{log\ 3}

x = \frac{log\ 243}{log\ 3}

Hence, the expression in base 10 is:

x = \frac{log\ 243}{log\ 3} or x = \frac{log_{10}\ 243}{log_{10}\ 3}

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