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2 years ago

Write an expression for the sequence of operations described below.

Mathematics

1 answer:

Murrr4er [49]2 years ago

3 0

Answer:

8+s+n

Step-by-step explanation:

Add s to 8=8+s

and add 3 to result=8+s+3

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A traffic light at a certain intersection is green 50% of the time, yellow 10% of the time, and red 40% of the time. A car appro

kati45 [8]

Answer:

$6.4\times 10^{-5} = 0.000064 = 0.0064\%$ .

Step-by-step explanation:

Probability that the car encounters a green light on the first day: $50 \% = 0.5$ .

To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be

$(0.5) \times 0.5 = 0.25$ .

Condition is met on the first two days and green light on the third day: $(0.5 \times 0.5) \times 0.5 = 0.125$ .
Condition is met on the first three days and green light on the fourth day: $(0.5 \times 0.5 \times 0.5) \times 0.5$ .

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be $(0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1$ .

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. $(0.5^{4} \times 0.1) \times 0.4$

Seventh day: $(0.5^{4} \times 0.1 \times 0.4 ) \times 0.4$
Eighth day: $(0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4$
Ninth day: $(0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4$
Tenth day: $(0.5^{4} \times 0.1 \times 0.4^4 ) \times 0.4 = 0.5^{4} \times 0.1 \times 0.4^{5}$

The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: $0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%$ .

6 0

2 years ago

Read 2 more answers

Two lines, C and D, are represented by the equations given below:

lakkis [162]

y=x+14 line 1

y=3x+2 line 2

These are both the equation of lines written in slope intercept form

y=mx+b where m is the slope and the point (0,b) is the y intercept.

The first line has a slope of m=1. The 2nd line has a slope of m=3

Since these lines have different slopes, they are not parallel, thus they will cross at some point. What you have to determine is where the lines cross, which will be a point (x,y) that is on both lines.

We already have y solved in terms of x from either equation so we can use substitution to solve the system.

Since y=x+14 from line 1, put x+14 in place of y in the equation of line 2.

x+14=3x+2

solve for x.

Subtract x from both sides...

14= 3x-x+2

14=2x+2

subtract 2 from both sides

14-2=2x

12=2x

divide both sides by 2

6=x

We now have the x value of the common point. Plug the value 6 in for x in one of the original equations and solve for y.

y=6+14

y=20

These two lines cross at the point (6,20) which is a point the two lines have in common.

Hope I helped (SharkieOwO)

3 0

2 years ago

Find the area of the triangle to the nearest tenth.

s344n2d4d5 [400]

Answer:

It C

Step-by-step explanation:

7 0

2 years ago

Fill in the table using this function rule. y=14-2x

Mamont248 [21]

Answer:

when x is:

1; y = 12

2; y = 10

5; y = 4

6; y = 2

Step-by-step explanation:

Substitute each value of x to obtain respective y values

3 0

2 years ago

A set of city temperatures in April are normally distributed with a mean of 19.7 degrees Celsius and a standard deviation of 2 d

Sati [7]

Answer:

19.77% of average city temperatures are higher than that of Cairo

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 19.7, \sigma = 2$